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Calculate R, V, R1=202, R2=502 Series and Parallel Calculation

Physics

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Answer

PT≈8.23 WP_T \approx 8.23 \, \text{W}

PT=40.32 WP_T = 40.32 \, \text{W}

Step-by-step solution

6 steps

Here are the calculations for total power (P) for both series and parallel configurations.

Given:
VT=24 VV_T = 24 \, \text{V}
R1=20 ΩR_1 = 20 \, \Omega
R2=50 ΩR_2 = 50 \, \Omega

Series Circuit Calculation

  1. Calculate the total resistance (RTR_T) for resistors in series.

    RT=R1+R2R_T = R_1 + R_2 RT=20 Ω+50 ΩR_T = 20 \, \Omega + 50 \, \Omega RT=70 ΩR_T = 70 \, \Omega
  2. Calculate the total current (ITI_T) using Ohm's Law.

    IT=VTRTI_T = \frac{V_T}{R_T} IT=24 V70 ΩI_T = \frac{24 \, \text{V}}{70 \, \Omega} IT=1235 A≈0.343 AI_T = \frac{12}{35} \, \text{A} \approx 0.343 \, \text{A}
  3. Calculate the total power (PTP_T) for the series circuit.

    PT=VT⋅ITP_T = V_T \cdot I_T PT=24 V⋅1235 AP_T = 24 \, \text{V} \cdot \frac{12}{35} \, \text{A} PT=28835 WP_T = \frac{288}{35} \, \text{W} PT≈8.23 W\boxed{P_T \approx 8.23 \, \text{W}}

    Parallel Circuit Calculation

  4. Calculate the total resistance (RTR_T) for resistors in parallel.

    1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} 1RT=120 Ω+150 Ω\frac{1}{R_T} = \frac{1}{20 \, \Omega} + \frac{1}{50 \, \Omega} 1RT=5100 Ω+2100 Ω\frac{1}{R_T} = \frac{5}{100 \, \Omega} + \frac{2}{100 \, \Omega} 1RT=7100 Ω\frac{1}{R_T} = \frac{7}{100 \, \Omega} RT=1007 Ω≈14.29 ΩR_T = \frac{100}{7} \, \Omega \approx 14.29 \, \Omega
  5. Calculate the total current (ITI_T) using Ohm's Law.

    IT=VTRTI_T = \frac{V_T}{R_T} IT=24 V1007 ΩI_T = \frac{24 \, \text{V}}{\frac{100}{7} \, \Omega} IT=24×7100 AI_T = \frac{24 \times 7}{100} \, \text{A} IT=168100 A=1.68 AI_T = \frac{168}{100} \, \text{A} = 1.68 \, \text{A}
  6. Calculate the total power (PTP_T) for the parallel circuit.

    PT=VT⋅ITP_T = V_T \cdot I_T PT=24 V⋅1.68 AP_T = 24 \, \text{V} \cdot 1.68 \, \text{A} PT=40.32 WP_T = 40.32 \, \text{W} PT=40.32 W\boxed{P_T = 40.32 \, \text{W}}
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