This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Right ramyz, let's go. When a satellite moves from a higher orbit to a lower orbit, the following energy changes occur: 1. Gravitational Potential Energy (U_g): The gravitational potential energy of a satellite in orbit is given by U_g = -(GMm)/(r), where G is the gravitational constant, M is the mass of the central body, m is the mass of the satellite, and r is the orbital radius. As the satellite moves from a higher orbit to a lower orbit, the orbital radius r decreases. Since U_g is negative and r decreases, the potential energy becomes more negative, which means the gravitational potential energy decreases. 2. Kinetic Energy (K): For a satellite in a stable circular orbit, the kinetic energy is given by K = (1)/(2)mv^2. The orbital speed v is related to the orbital radius by v = sqrt((GM)/(r)). Substituting this into the kinetic energy formula: K = (1)/(2)m (sqrt((GM)/(r)))^2 = (1)/(2) (GMm)/(r) As the satellite moves from a higher orbit to a lower orbit, r decreases. Therefore, the kinetic energy K increases. 3. Total Energy (E): The total energy of the satellite is the sum of its kinetic and gravitational potential energy: E = K + U_g = (1)/(2) (GMm)/(r) - (GMm)/(r) = -(1)/(2) (GMm)/(r) As the satellite moves from a higher orbit to a lower orbit, r decreases. Since E is negative and r decreases, the total energy becomes more negative, which means the total energy decreases. Comparing these changes with the given options: Kinetic energy: increases Gravitational potential energy: decreases Total energy: decreases This matches option C. The final answer is C. Send me the next one 📸