Silicon has a density of 2.23g/cm3 and atomic mass of 28.09g/mol calculate the number of atom in 1cm3 of silicon

Physics

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Answer

4.781×1022 atoms4.781 \times 10^{22}\text{ atoms}

Step-by-step solution

3 steps
  1. Calculate the mass of silicon in 1 cm31\text{ cm}^3.

    The density of silicon is given as 2.23 gcm32.23\ \frac{\text{g}}{\text{cm}^3}.
    Mass = Density ×\times Volume

    Mass=2.23 gcm3×1 cm3=2.23 g\text{Mass} = 2.23\ \frac{\text{g}}{\text{cm}^3} \times 1\text{ cm}^3 = 2.23\text{ g}
  2. Calculate the number of moles of silicon in 1 cm31\text{ cm}^3.

    The atomic mass of silicon is 28.09 gmol28.09\ \frac{\text{g}}{\text{mol}}.
    Number of moles = MassAtomic Mass\frac{\text{Mass}}{\text{Atomic Mass}}

    Number of moles=2.23 g28.09 gmol≈0.07938 mol\text{Number of moles} = \frac{2.23\text{ g}}{28.09\ \frac{\text{g}}{\text{mol}}} \approx 0.07938\text{ mol}
  3. Calculate the number of atoms in 1 cm31\text{ cm}^3 of silicon.

    Use Avogadro's number, which is 6.022×1023 atomsmol6.022 \times 10^{23}\ \frac{\text{atoms}}{\text{mol}}.
    Number of atoms = Number of moles ×\times Avogadro's number

    Number of atoms=0.07938 mol×6.022×1023 atomsmol\text{Number of atoms} = 0.07938\text{ mol} \times 6.022 \times 10^{23}\ \frac{\text{atoms}}{\text{mol}} Number of atoms≈4.781×1022 atoms\text{Number of atoms} \approx 4.781 \times 10^{22}\text{ atoms}

    The number of atoms in 1 cm31\text{ cm}^3 of silicon is:

    4.781×1022 atoms4.781 \times 10^{22}\text{ atoms}
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