We read your photo as:

Start with the expression for displacement s derived from average velocity and time.

Physics

ScanSolve AI Answer

Step-by-step solution

6 steps

Here is the derivation of the kinematic equation:

  1. Start with the expression for displacement ss derived from average velocity and time.

    s=(v+u2)×(v−ua)s = \left(\frac{v+u}{2}\right) \times \left(\frac{v-u}{a}\right)
  2. Combine the terms into a single fraction.

    s=(v+u)(v−u)2as = \frac{(v+u)(v-u)}{2a}
  3. Expand the numerator using the difference of squares formula, (x+y)(x−y)=x2−y2(x+y)(x-y) = x^2 - y^2.

    s=v2−uv+uv−u22as = \frac{v^2 - uv + uv - u^2}{2a}
  4. Simplify the numerator by canceling out the uvuv terms.

    s=v2−u22as = \frac{v^2 - u^2}{2a}
  5. Multiply both sides by 2a2a to isolate v2−u2v^2 - u^2.

    2as=v2−u22as = v^2 - u^2
  6. Rearrange the equation to solve for v2v^2.

    v2=u2+2asv^2 = u^2 + 2as

    This is the final kinematic equation.

    The student's work is ✅ Correct.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp