Here is the derivation of the kinematic equation: Step 1: Start with the expression for displacement $s$ derived from average velocity and time. $$s = \left(\frac{v+u}{2}\right) \times \left(\frac{v-u}{a}\right)$$ Step 2: Combine the terms into a single fraction. $$s = \frac{(v+u)(v-u)}{2a}$$ Step 3: Expand the numerator using the difference of squares formula, $(x+y)(x-y) = x^2 - y^2$. $$s = \frac{v^2 - uv + uv - u^2}{2a}$$ Step 4: Simplify the numerator by canceling out the $uv$ terms. $$s = \frac{v^2 - u^2}{2a}$$ Step 5: Multiply both sides by $2a$ to isolate $v^2 - u^2$. $$2as = v^2 - u^2$$ Step 6: Rearrange the equation to solve for $v^2$. $$v^2 = u^2 + 2as$$ This is the final kinematic equation. The student's work is ✅ Correct. Send me the next one 📸