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Temperature measurement can be divided into two categories that is, electrical and non-electrical methods. List three (3) types of thermometer in each case.

Physics

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2. a. List the three (3) types of measuring instruments and give an example for each.
The question refers to characteristics of measuring instruments:

  • i) Accuracy: This refers to how close a measurement is to the true or accepted value.
    • Example: A thermometer that consistently reads 25.0∘C25.0^\circ\text{C} when the actual temperature is 25.0∘C25.0^\circ\text{C} is accurate.
  • ii) Precision: This refers to the reproducibility or consistency of repeated measurements. It indicates how close multiple measurements are to each other, regardless of their closeness to the true value.
    • Example: A scale that repeatedly measures a 10 kg object as 10.2 kg, 10.2 kg, and 10.2 kg is precise, even if it's not accurate.
  • iii) Resolution: This is the smallest change in the measured quantity that an instrument can detect and display.
    • Example: A digital voltmeter that can display readings to three decimal places (e.g., 1.234 V) has a higher resolution than one that only displays to one decimal place (e.g., 1.2 V).

2. b. Temperature measurement can be divided into two categories that is, electrical and non-electrical methods. List three (3) types of thermometer in each case.

  • Electrical Thermometers:
    1. Resistance Temperature Detector (RTD): Measures temperature based on the change in electrical resistance of a metal (e.g., platinum).
    2. Thermistor: Measures temperature based on the change in electrical resistance of a semiconductor material.
    3. Thermocouple: Measures temperature based on the voltage generated at the junction of two dissimilar metals.
  • Non-Electrical Thermometers:
    1. Liquid-in-glass thermometer: Measures temperature based on the thermal expansion of a liquid (e.g., mercury or alcohol) in a sealed glass tube.
    2. Bimetallic thermometer: Measures temperature based on the differential thermal expansion of two bonded metals, causing a strip to bend.
    3. Gas thermometer: Measures temperature based on the change in pressure or volume of a gas.

2. c. A second order is described by the differential equation 0.15d2ydt2+0.3dydt+5y=5x0.15 \frac{d^2y}{dt^2} + 0.3 \frac{dy}{dt} + 5y = 5x, where xx is the input and yy the output. By comparing the equation with the standard second order form, determine:

The given differential equation is:

0.15d2ydt2+0.3dydt+5y=5x0.15 \frac{d^2y}{dt^2} + 0.3 \frac{dy}{dt} + 5y = 5x

The standard form of a second-order differential equation is:

d2ydt2+2ζωndydt+ωn2y=K′x\frac{d^2y}{dt^2} + 2\zeta\omega_n \frac{dy}{dt} + \omega_n^2 y = K'x

To compare, divide the given equation by 0.15:

d2ydt2+0.30.15dydt+50.15y=50.15x\frac{d^2y}{dt^2} + \frac{0.3}{0.15} \frac{dy}{dt} + \frac{5}{0.15} y = \frac{5}{0.15} x d2ydt2+2dydt+1003y=1003x\frac{d^2y}{dt^2} + 2 \frac{dy}{dt} + \frac{100}{3} y = \frac{100}{3} x
  1. Determine the system undamped natural frequency (ωn\omega_n).

    Comparing the coefficient of yy with ωn2\omega_n^2:

    ωn2=1003\omega_n^2 = \frac{100}{3} ωn=1003=103=1033 rad/s\omega_n = \sqrt{\frac{100}{3}} = \frac{10}{\sqrt{3}} = \frac{10\sqrt{3}}{3} \, \text{rad/s}

    The system undamped natural frequency is 1033 rad/s≈5.77 rad/s\boxed{\frac{10\sqrt{3}}{3} \, \text{rad/s} \approx 5.77 \, \text{rad/s}}.

  2. Determine the damping ratio (ζ\zeta).

    Comparing the coefficient of dydt\frac{dy}{dt} with 2ζωn2\zeta\omega_n:

    2ζωn=22\zeta\omega_n = 2 ζωn=1\zeta\omega_n = 1

    Substitute the value of ωn\omega_n:

    ζ(103)=1\zeta \left(\frac{10}{\sqrt{3}}\right) = 1 ζ=310\zeta = \frac{\sqrt{3}}{10}

    The damping ratio is 310≈0.173\boxed{\frac{\sqrt{3}}{10} \approx 0.173}.

    2. d. A temperature measuring instrument incorporates a platinum resistance thermometer, a Wheatstone bridge, a voltage amplifier and a pen recorder. The individual sensitivities are:

    • Resistance transducer = 0.36 Ω/∘C0.36 \, \Omega/^\circ\text{C}
    • Wheatstone bridge = 0.01 V/Ω0.01 \, \text{V}/\Omega
    • Amplifier = +10 V/V+10 \, \text{V/V}
    • Pen recorder = 0.2 cm/V0.2 \, \text{cm/V}
  3. Calculate the overall sensitivity of the system.

    The overall sensitivity (SoverallS_{overall}) is the product of the individual sensitivities:

    Soverall=Stransducer×Sbridge×Samplifier×SrecorderS_{overall} = S_{transducer} \times S_{bridge} \times S_{amplifier} \times S_{recorder} Soverall=(0.36 Ω/∘C)×(0.01 V/Ω)×(10 V/V)×(0.2 cm/V)S_{overall} = (0.36 \, \Omega/^\circ\text{C}) \times (0.01 \, \text{V}/\Omega) \times (10 \, \text{V/V}) \times (0.2 \, \text{cm/V}) Soverall=0.36×0.01×10×0.2 cm/∘CS_{overall} = 0.36 \times 0.01 \times 10 \times 0.2 \, \text{cm}/^\circ\text{C} Soverall=0.0072 cm/∘CS_{overall} = 0.0072 \, \text{cm}/^\circ\text{C}

    The overall sensitivity of the system is 0.0072 cm/∘C\boxed{\text{0.0072 cm/}^\circ\text{C}}.

  4. Calculate the temperature change corresponding to a recorded pen movement of 4 cm.

    Let ΔL\Delta L be the pen movement and ΔT\Delta T be the temperature change.

    ΔL=Soverall×ΔT\Delta L = S_{overall} \times \Delta T 4 cm=(0.0072 cm/∘C)×ΔT4 \, \text{cm} = (0.0072 \, \text{cm}/^\circ\text{C}) \times \Delta T ΔT=4 cm0.0072 cm/∘C\Delta T = \frac{4 \, \text{cm}}{0.0072 \, \text{cm}/^\circ\text{C}} ΔT=555.555... ∘C\Delta T = 555.555... \, ^\circ\text{C}

    The temperature change corresponding to a recorded pen movement of 4 cm is 555.56∘C\boxed{\text{555.56}^\circ\text{C}}.

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