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The air column in a closed pipe of length 50 cm is set into vibration to generate a wave at its fundamental frequency. i. Sketch the diagram of the wave generated. ii. Calculate I. its wavelength. II. the frequency of the first overtone. [Speed of sound in air = 340 ms-1]
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Step-by-step solution
6 stepsHere's the solution for part (c):
Part c(i)
Sketch the diagram of the wave generated
For a closed pipe at its fundamental frequency, there is a node at the closed end and an antinode at the open end. This corresponds to one-quarter of a wavelength.
Open End (Antinode)
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| Node (Closed End)
Part c(ii)
Calculate
I. Its wavelength.
State the given length of the pipe and convert to meters.
The length of the closed pipe, .
Relate the pipe length to the wavelength for the fundamental frequency in a closed pipe.
For the fundamental frequency in a closed pipe, the length of the pipe is one-quarter of the wavelength ().
Calculate the wavelength.
The wavelength is .
II. The frequency of the first overtone.
State the speed of sound in air.
Speed of sound in air, .
Calculate the fundamental frequency ().
Using the wave speed formula , we can find the fundamental frequency:
Determine the frequency of the first overtone.
For a closed pipe, the overtones are odd multiples of the fundamental frequency. The first overtone is the third harmonic ().
The frequency of the first overtone is .
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