The displacement s metres of a particle moving along a straight line after t seconds is given by s=3t + 3/2 t2 - 2t3.

Tunatumia fomula $y = \sin 2x$ kwa kila thamani ya $x$.

• Kwa $x = 60^\circ$: $\sin(2 \times 60^\circ) = \sin(120^\circ) = \frac{\sqrt{3}}{2} \approx 0.87$
• Kwa $x = 90^\circ$: $\sin(2 \times 90^\circ) = \sin(180^\circ) = 0.00$
• Kwa $x = 150^\circ$: $\sin(2 \times 150^\circ) = \sin(300^\circ) = -\frac{\sqrt{3}}{2} \approx -0.87$
• Kwa $x = 270^\circ$: $\sin(2 \times 270^\circ) = \sin(540^\circ) = \sin(180^\circ) = 0.00$
• Kwa $x = 300^\circ$: $\sin(2 \times 300^\circ) = \sin(600^\circ) = \sin(240^\circ) = -\frac{\sqrt{3}}{2} \approx -0.87$
• Kwa $x = 330^\circ$: $\sin(2 \times 330^\circ) = \sin(660^\circ) = \sin(300^\circ) = -\frac{\sqrt{3}}{2} \approx -0.87$

Tunatumia fomula $y = 3 \cos x - 2$ kwa kila thamani ya $x$.

• Kwa $x = 60^\circ$: $3 \cos(60^\circ) - 2 = 3(0.5) - 2 = 1.5 - 2 = -0.50$
• Kwa $x = 180^\circ$: $3 \cos(180^\circ) - 2 = 3(-1) - 2 = -3 - 2 = -5.00$
• Kwa $x = 240^\circ$: $3 \cos(240^\circ) - 2 = 3(-0.5) - 2 = -1.5 - 2 = -3.50$
• Kwa $x = 270^\circ$: $3 \cos(270^\circ) - 2 = 3(0) - 2 = -2.00$
• Kwa $x = 330^\circ$: $3 \cos(330^\circ) - 2 = 3(\frac{\sqrt{3}}{2}) - 2 \approx 3(0.8660) - 2 = 2.598 - 2 = 0.598 \approx 0.60$

Jedwali lililokamilika ni:

$$\boxed{ \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|c|c|c|} \hline x^\circ & 0 & 30 & 60 & 90 & 120 & 150 & 180 & 210 & 240 & 270 & 300 & 330 & 360 \\ \hline \text{Sin } 2x & 0.00 & 0.87 & 0.87 & 0.00 & -0.87 & -0.87 & 0.00 & 0.87 & 0.87 & 0.00 & -0.87 & -0.87 & 0.00 \\ \hline 3 \cos x - 2 & 1.00 & 0.60 & -0.50 & -2.00 & -3.50 & -4.60 & -5.00 & -4.60 & -3.50 & -2.00 & -0.50 & 0.60 & 1.00 \\ \hline \end{array} }$$