Step 1: Identify the general form of a wave equation. The general equation for a sinusoidal wave traveling in the positive x-direction is given by: $$y = A \sin(\omega t - kx)$$ where $A$ is the amplitude, $\omega$ is the angular frequency, and $k$ is the wave number. Step 2: Rewrite the given equation in the standard form. The given equation is $y = 15 \sin \left(2\pi \cdot 5 (60t - x)\right)$. First, distribute the $2\pi \cdot 5$ term inside the parenthesis: $$y = 15 \sin \left( (2\pi \cdot 5 \cdot 60)t - (2\pi \cdot 5)x \right)$$ $$y = 15 \sin \left( 600\pi t - 10\pi x \right)$$ Step 3: Compare with the standard form to find the wave number $k$. By comparing $y = 15 \sin \left( 600\pi t - 10\pi x \right)$ with $y = A \sin(\omega t - kx)$, we can identify: $\omega = 600\pi$ $k = 10\pi$ Step 4: Calculate the wavelength $\lambda$ using the wave number $k$. The relationship between the wave number $k$ and the wavelength $\lambda$ is: $$k = \frac{2\pi}{\lambda}$$ Substitute the value of $k$ we found: $$10\pi = \frac{2\pi}{\lambda}$$ Step 5: Solve for $\lambda$. Divide both sides by $2\pi$: $$\lambda = \frac{2\pi}{10\pi}$$ $$\lambda = \frac{2}{10}$$ $$\lambda = 0.2$$ The wavelength of the wave is 0.2 units. The final answer is $\boxed{0.2}$.