This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
The formula for potential difference across the galvanometer (which is the potential difference of the Wheatstone bridge when it's unbalanced) is derived from Kirchhoff's laws. Let the resistances be R_1, R_2, R_3, R_4 and the galvanometer resistance be R_g. Let the supply voltage be V. V_AB = V (R_2)/(R_1 + R_2) V_AD = V (R_4)/(R_3 + R_4) The potential difference across the galvanometer (V_g) is the difference between these two potentials: V_g = V_AB - V_AD = V ( (R_2)/(R_1 + R_2) - (R_4)/(R_3 + R_4) ) This can be simplified to: V_g = V (R_2 R_3 - R_1 R_4)/((R_1 + R_2)(R_3 + R_4)) The bridge is balanced when V_g = 0, which implies R_2 R_3 = R_1 R_4. Send me the next one 📸