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An electronic circuit needs a potential difference of 3,6 V across a resistor when it has a current of 30 mA. Will the voltage still be 3,6 V if the resistor has a resistance of 96 Ω? Answer Yes or No. Justify your response with a calculation.

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2 parts
7.7

0.4 A0.4 \text{ A}

7.8

No, V=2.88 V\text{No, } V = 2.88 \text{ V}

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Part 7.7· 2 steps

A bulb operates from a 220 V supply. The resistance is 550 Ω. Calculate the strength of the current when it is lit.

  1. Identify the given values.

    Voltage (VV) = 220 V220 \text{ V}
    Resistance (RR) = 550 Ω550 \ \Omega

  2. Use Ohm's Law to calculate the current (I=VRI = \frac{V}{R}).

    I=220 V550 ΩI = \frac{220 \text{ V}}{550 \ \Omega} I=0.4 AI = 0.4 \text{ A}

    The strength of the current is 0.4 A.

    0.4 A\boxed{0.4 \text{ A}}

Part 7.8

No, V=2.88 V\text{No, } V = 2.88 \text{ V}

An electronic circuit needs a potential difference of 3.6 V across a resistor when it has a current of 30 mA. Will the voltage still be 3.6 V if the resistor has a resistance of 96 Ω? Answer Yes or No. Justify your response with a calculation.

  1. Identify the given values for the new scenario.

    Current (II) = 30 mA30 \text{ mA}
    Resistance (RR) = 96 Ω96 \ \Omega

  2. Convert the current from milliamperes (mA) to amperes (A).

    I=30 mA=30×10−3 A=0.030 AI = 30 \text{ mA} = 30 \times 10^{-3} \text{ A} = 0.030 \text{ A}
  3. Calculate the voltage (VV) across the resistor using Ohm's Law (V=I×RV = I \times R).

    V=0.030 A×96 ΩV = 0.030 \text{ A} \times 96 \ \Omega V=2.88 VV = 2.88 \text{ V}
  4. Compare the calculated voltage to the required voltage of 3.6 V.

    Since 2.88 V≠3.6 V2.88 \text{ V} \neq 3.6 \text{ V}, the voltage will not still be 3.6 V.

    No, the voltage will not still be 3.6 V. It will be 2.88 V.\text{No, the voltage will not still be } 3.6 \text{ V. It will be } 2.88 \text{ V.} No, V=2.88 V\boxed{\text{No, } V = 2.88 \text{ V}}
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