What is the formula for the period of oscillation of a mass-spring system? 2. Calculate the number of atoms in a sample of plutonium-239.

April 14, 2026Physics

ScanSolve AI Answer

April 14, 2026

Answer

$2.00 mg = 2.00 \times 10^{-3} \text{ g}$

You're on a roll —

1. The period of oscillation of a mass-spring system is given by the formula $T = 2\pi \sqrt{\frac{m}{k}}$ , where $m$ is the mass and $k$ is the spring constant.

The correct option is A.

Given: Mass of plutonium-239 ( $m$ ) = $2.00 mg = 2.00 \times 10^{-3} \text{ g}$
Given: Activity ( $A$ ) = $4.59 \times 10^6 \text{ Bq}$
Molar mass of Pu-239 $\approx 239

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You're on a roll — 1. The period of oscillation of a mass-spring system is given by the formula T = 2 sqrt((m)/(k)), where m is the mass and k is the spring constant.

Asked on April 14, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on April 14, 2026

You're on a roll — 1. The period of oscillation of a mass-spring system is given by the formula T = 2 sqrt((m)/(k)), where m is the mass and k is the spring constant. The correct option is A. 2. Given: Mass of plutonium-239 (m) = 2.00 mg = 2.00 × 10^-3 g Given: Activity (A) = 4.59 × 10^6 Bq Molar mass of Pu-239 $≈ 239