The formula shown is for the average translational kinetic energy of a molecule in an ideal gas.
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
The formula shown is for the average translational kinetic energy of a molecule in an ideal gas.
$$ K.E = \frac{3}{2} k_B T $$
Here:
• $K.E$ represents the average translational kinetic energy of a single molecule.
• $k_B$ is the Boltzmann constant, which relates the average kinetic energy of particles in a gas to the temperature of the gas. Its value is approximately $1.38 \times 10^{-23} \text{ J/K}$.
• $T$ is the absolute temperature of the gas in Kelvin.
This formula is correct for the average translational kinetic energy of a molecule in a monatomic ideal gas.
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