The formula shown is for the average translational kinetic energy of a molecule in an ideal gas.

The formula shown is for the average translational kinetic energy of a molecule in an ideal gas.

$$K.E = \frac{3}{2} k_B T$$

Here:

• $K.E$ represents the average translational kinetic energy of a single molecule.
• $k_B$ is the Boltzmann constant, which relates the average kinetic energy of particles in a gas to the temperature of the gas. Its value is approximately $1.38 \times 10^{-23} \text{ J/K}$.
• $T$ is the absolute temperature of the gas in Kelvin.

This formula is correct for the average translational kinetic energy of a molecule in a monatomic ideal gas.