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The question "ii. The current flowing through the 8 resistor" is incomplete as it refers to an 8-ohm resistor without a circuit diagram or further context. Please provide the full question or diagram

Physics

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2 parts
c(i)

4.2 KW\text{4.2 KW}

c(ii)

17.5 A\text{17.5 A}

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The question "ii. The current flowing through the 8 resistor" is incomplete as it refers to an 8-ohm resistor without a circuit diagram or further context. Please provide the full question or diagram for this part.

Let's proceed with part (c) about the house appliances.

Part c(i)· 3 steps

The total power in KW used when all are switched on.

A house has twenty 60W60\text{W} bulbs, two 1000W1000\text{W} heater and two 500W500\text{W} security lights. If the appliances are running on a 240V240\text{V} supply calculate

  1. Calculate the total power consumed by each type of appliance.

    Power from bulbs: Pbulbs=20×60 W=1200 WP_{\text{bulbs}} = 20 \times 60\text{ W} = 1200\text{ W}
    Power from heaters: Pheaters=2×1000 W=2000 WP_{\text{heaters}} = 2 \times 1000\text{ W} = 2000\text{ W}
    Power from security lights: Plights=2×500 W=1000 WP_{\text{lights}} = 2 \times 500\text{ W} = 1000\text{ W}

  2. Calculate the total power in Watts.

    Ptotal=Pbulbs+Pheaters+PlightsP_{\text{total}} = P_{\text{bulbs}} + P_{\text{heaters}} + P_{\text{lights}} Ptotal=1200 W+2000 W+1000 WP_{\text{total}} = 1200\text{ W} + 2000\text{ W} + 1000\text{ W} Ptotal=4200 WP_{\text{total}} = 4200\text{ W}
  3. Convert the total power from Watts to Kilowatts (KW).

    Ptotal (KW)=4200 W1000 W/KWP_{\text{total (KW)}} = \frac{4200\text{ W}}{1000\text{ W/KW}} Ptotal (KW)=4.2 KWP_{\text{total (KW)}} = 4.2\text{ KW}

    The total power used is 4.2 KW\boxed{\text{4.2 KW}}.

Part c(ii)

17.5 A\text{17.5 A}

The total current drawn from the mains supply.

  1. Use the formula relating power, voltage, and current.

    P=VIP = VI

    Where PP is total power, VV is voltage, and II is current.

  2. Rearrange the formula to solve for current.

    I=PVI = \frac{P}{V}
  3. Substitute the total power (in Watts) and the supply voltage.

    I=4200 W240 VI = \frac{4200\text{ W}}{240\text{ V}} I=17.5 AI = 17.5\text{ A}

    The total current drawn from the mains supply is 17.5 A\boxed{\text{17.5 A}}.

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