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The refractive index of a glass is 1.5 and that of water is 1.33. If the speed of light in water is 2.25x10⁸ m/s, what is the speed of light in glass?

Physics

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Answer

1.995×108 m/s\text{1.995} \times 10^8 \text{ m/s}

Step-by-step solution

4 steps

Ili kutatua tatizo hili, tutatumia uhusiano kati ya fahirisi ya mtawanyiko (refractive index) na kasi ya mwanga katika vyombo tofauti.

  • Fahirisi ya mtawanyiko wa kioo (ngn_g) = 1.5
  • Fahirisi ya mtawanyiko wa maji (nwn_w) = 1.33 (kutoka "1:8 13" ambayo inamaanisha 1.33)
  • Kasi ya mwanga ndani ya maji (vwv_w) = 2.25×108 m/s2.25 \times 10^8 \text{ m/s}
  • Tunahitaji kupata kasi ya mwanga ndani ya kioo (vgv_g).

Kanuni inayohusisha fahirisi ya mtawanyiko na kasi ya mwanga ni:

n1v1=n2v2n_1 v_1 = n_2 v_2

Ambapo nn ni fahirisi ya mtawanyiko na vv ni kasi ya mwanga katika kati husika.

  1. Andika data ulizopewa.

    • Fahirisi ya mtawanyiko wa kioo, ng=1.5n_g = 1.5
    • Fahirisi ya mtawanyiko wa maji, nw=1.33n_w = 1.33
    • Kasi ya mwanga ndani ya maji, vw=2.25×108 m/sv_w = 2.25 \times 10^8 \text{ m/s}
  2. Tumia kanuni inayohusisha fahirisi ya mtawanyiko na kasi ya mwanga.

    Tunatumia kanuni:

    ngvg=nwvwn_g v_g = n_w v_w
  3. Panga upya kanuni ili kupata kasi ya mwanga ndani ya kioo (vgv_g).

    vg=nwvwngv_g = \frac{n_w v_w}{n_g}
  4. Badilisha thamani ulizopewa kwenye kanuni na ufanye hesabu.

    vg=1.33×(2.25×108 m/s)1.5v_g = \frac{1.33 \times (2.25 \times 10^8 \text{ m/s})}{1.5} vg=2.9925×108 m/s1.5v_g = \frac{2.9925 \times 10^8 \text{ m/s}}{1.5} vg=1.995×108 m/sv_g = 1.995 \times 10^8 \text{ m/s}

    Kasi ya mwanga ndani ya kioo ni:

    1.995×108 m/s\text{1.995} \times 10^8 \text{ m/s}
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