The refractive index of waters is 1.33 Calculate the critical angle State whether total internal refraction occurs at 50°

Physics

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Answer

48.75°\text{48.75°}

Step-by-step solution

2 steps
  1. Calculate the critical angle.

    The formula for the critical angle (θc\theta_c) is given by:

    sin⁡(θc)=1n\sin(\theta_c) = \frac{1}{n}

    where nn is the refractive index.
    Given n=1.33n = 1.33.

    Substitute the value of nn:

    sin⁡(θc)=11.33\sin(\theta_c) = \frac{1}{1.33} sin⁡(θc)≈0.75188\sin(\theta_c) \approx 0.75188

    To find θc\theta_c, take the inverse sine:

    θc=arcsin⁡(0.75188)\theta_c = \arcsin(0.75188) θc≈48.75°\theta_c \approx \boxed{\text{48.75°}}
  2. State whether total internal reflection occurs at 50°.

    Total internal reflection occurs when the angle of incidence is greater than the critical angle.
    The calculated critical angle (θc\theta_c) is approximately 48.75∘48.75^\circ.
    The given angle of incidence is 50∘50^\circ.

    Since 50∘>48.75∘50^\circ > 48.75^\circ, total internal reflection does occur.

    Total internal reflection occurs at 50° because 50∘>48.75∘\text{Total internal reflection occurs at 50° because } 50^\circ > 48.75^\circ
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