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The rule for reflection across the x-axis is (x, y) (x, -y).

Physics

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1. Reflect the point A (−3,7)(-3, 7) in the x-axis.

  1. The rule for reflection across the x-axis is (x,y)→(x,−y)(x, y) \to (x, -y).

  2. Apply the rule to point A(−3,7)A(-3, 7).

    A′(−3,−(7))=A′(−3,−7)A'(-3, -(7)) = A'(-3, -7)

    The coordinates of the image are (−3,−7)\boxed{(-3, -7)}.

    2. Reflect the point B (6,−2)(6, -2) in the line y=xy = x.

  3. The rule for reflection across the line y=xy = x is (x,y)→(y,x)(x, y) \to (y, x).

  4. Apply the rule to point B(6,−2)B(6, -2).

    B′(−2,6)B'(-2, 6)

    The coordinates of the image are (−2,6)\boxed{(-2, 6)}.

    3. Rotate the point C (−4,5)(-4, 5) by 180 degrees about the origin.

  5. The rule for rotation by 180 degrees about the origin is (x,y)→(−x,−y)(x, y) \to (-x, -y).

  6. Apply the rule to point C(−4,5)C(-4, 5).

    C′(−(−4),−(5))=C′(4,−5)C'(-(-4), -(5)) = C'(4, -5)

    The coordinates of the image are (4,−5)\boxed{(4, -5)}.

    4. Rotate the point D (2,−3)(2, -3) by 90 degrees counter-clockwise about the origin.

  7. The rule for rotation by 90 degrees counter-clockwise about the origin is (x,y)→(−y,x)(x, y) \to (-y, x).

  8. Apply the rule to point D(2,−3)D(2, -3).

    D′(−(−3),2)=D′(3,2)D'(-(-3), 2) = D'(3, 2)

    The coordinates of the image are (3,2)\boxed{(3, 2)}.

    5. A square has vertices at (0,0)(0, 0), (2,0)(2, 0), (2,2)(2, 2), and (0,2)(0, 2). Find the image after reflecting in the y-axis.

  9. The rule for reflection across the y-axis is (x,y)→(−x,y)(x, y) \to (-x, y).

  10. Apply the rule to each vertex.

    For (0,0)(0, 0): (−0,0)=(0,0)(-0, 0) = (0, 0)
    For (2,0)(2, 0): (−2,0)(-2, 0)
    For (2,2)(2, 2): (−2,2)(-2, 2)
    For (0,2)(0, 2): (−0,2)=(0,2)(-0, 2) = (0, 2)
    The coordinates of the image are (0,0),(−2,0),(−2,2),(0,2)\boxed{(0, 0), (-2, 0), (-2, 2), (0, 2)}.

    6. Reflect the point E (−5,−8)(-5, -8) in the line y=−xy = -x.

  11. The rule for reflection across the line y=−xy = -x is (x,y)→(−y,−x)(x, y) \to (-y, -x).

  12. Apply the rule to point E(−5,−8)E(-5, -8).

    E′(−(−8),−(−5))=E′(8,5)E'(-(-8), -(-5)) = E'(8, 5)

    The coordinates of the image are (8,5)\boxed{(8, 5)}.

    7. Reflect the point F (7,−3)(7, -3) in the y-axis. Then reflect that image in the x-axis.

  13. First, reflect F(7,−3)F(7, -3) in the y-axis.

    The rule is (x,y)→(−x,y)(x, y) \to (-x, y).

    F′(−7,−3)F'(-7, -3)
  14. Next, reflect F′(−7,−3)F'(-7, -3) in the x-axis.

    The rule is (x,y)→(x,−y)(x, y) \to (x, -y).

    F′′(−7,−(−3))=F′′(−7,3)F''(-7, -(-3)) = F''(-7, 3)

    The final coordinates are (−7,3)\boxed{(-7, 3)}.

    8. Rotate the point G (6,2)(6, 2) by 270 degrees counter-clockwise about the origin.

  15. The rule for rotation by 270 degrees counter-clockwise about the origin is (x,y)→(y,−x)(x, y) \to (y, -x).

  16. Apply the rule to point $G(6, 2)$.

    G′(2,−6)G'(2, -6)

    The coordinates of the image are (2,−6)\boxed{(2, -6)}.

    9. A triangle has vertices at P (−2,1)(-2, 1), Q (0,4)(0, 4), and R (3,−1)(3, -1). Rotate the triangle by 90 degrees counter-clockwise about the origin.

  17. The rule for rotation by 90 degrees counter-clockwise about the origin is (x,y)→(−y,x)(x, y) \to (-y, x).

  18. Apply the rule to each vertex.

    For P(−2,1)P(-2, 1): P′(−1,−2)P'(-1, -2)
    For Q(0,4)Q(0, 4): Q′(−4,0)Q'(-4, 0)
    For R(3,−1)R(3, -1): R′(−(−1),3)=R′(1,3)R'(-(-1), 3) = R'(1, 3)
    The coordinates of the image triangle P'Q'R' are P′(−1,−2),Q′(−4,0),R′(1,3)\boxed{P'(-1, -2), Q'(-4, 0), R'(1, 3)}.

    10. A rectangle has vertices at (−4,1)(-4, 1), (−4,5)(-4, 5), (3,5)(3, 5), and (3,1)(3, 1). Reflect the rectangle in the line y=xy = x.

  19. The rule for reflection across the line y=xy = x is (x,y)→(y,x)(x, y) \to (y, x).

  20. Apply the rule to each vertex.

    For (−4,1)(-4, 1): (1,−4)(1, -4)
    For (−4,5)(-4, 5): (5,−4)(5, -4)
    For (3,5)(3, 5): (5,3)(5, 3)
    For (3,1)(3, 1): (1,3)(1, 3)
    The coordinates of the image rectangle are (1,−4),(5,−4),(5,3),(1,3)\boxed{(1, -4), (5, -4), (5, 3), (1, 3)}.

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