The uniform beam PQ of mass 5kg is pivoted at point X as shown if force F is 2m from end Q,find the value of F , if PQ is 20m

This problem requires information from a diagram ("as shown") to determine the exact position of the pivot point X. Without this information, the problem cannot be solved uniquely.

However, I will make a common assumption for such problems: that the beam is in equilibrium, and the pivot X is located such that the moment due to the beam's weight is balanced by the moment due to force F.

Assumptions:

1. The beam is uniform, so its weight acts at its center.
2. The beam is in rotational equilibrium, meaning the sum of clockwise moments about the pivot equals the sum of anticlockwise moments.
3. Both the beam's weight and force F act downwards.
4. The pivot X is located between the point where the weight