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Physics

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Step-by-step solution

7 steps
  1. Identify the given information.

    Mass of the object (mm) = 10 kg
    Initial velocity (viv_i) = 5 m/s
    Final velocity (vfv_f) = 15 m/s
    Time interval (Δt\Delta t) = 4 s

  2. Determine the acceleration of the object.

    Acceleration (aa) is the rate of change of velocity. The formula is:
    a=vf−viΔta = \frac{v_f - v_i}{\Delta t}

  3. Substitute the given values into the acceleration formula.

    a=15 m/s−5 m/s4 sa = \frac{15 \, \text{m/s} - 5 \, \text{m/s}}{4 \, \text{s}}

  4. Calculate the acceleration.

    a=10 m/s4 sa = \frac{10 \, \text{m/s}}{4 \, \text{s}}
    a=2.5 m/s2a = 2.5 \, \text{m/s}^2

  5. Calculate the net force acting on the object.

    According to Newton's second law of motion, the net force (FnetF_{net}) is the product of mass and acceleration:
    Fnet=m×aF_{net} = m \times a

  6. Substitute the mass and calculated acceleration into the formula.

    Fnet=10 kg×2.5 m/s2F_{net} = 10 \, \text{kg} \times 2.5 \, \text{m/s}^2

  7. Calculate the net force.

    Fnet=25 kg⋅m/s2F_{net} = 25 \, \text{kg} \cdot \text{m/s}^2
    Since 1 Newton (N) is equal to 1 kg·m/s², the net force is:
    Fnet=25 NF_{net} = 25 \, \text{N}

    The net force acting on the object is 25 N.

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