We read your photo as:

To calculate the electric field intensity at a point in air situated at a distance of 2 m from a charge. The value of the charge is partially cut off in the image. I will assume the charge is the el

Physics

ScanSolve AI Answer

Answer

3.6×10−10 N/C\mathbf{3.6 \times 10^{-10} \text{ N/C}}

Step-by-step solution

3 steps

Here is the solution for question 2.

The question asks to calculate the electric field intensity at a point in air situated at a distance of 2 m from a charge. The value of the charge is partially cut off in the image. I will assume the charge is the elementary charge, q=1.6×10−19q = 1.6 \times 10^{-19} C, as it is a common value in such problems and appears in your notes above this question. If the charge value is different, please provide it.

Constants used:

  • Coulomb's constant, k=9×109 N m2/C2k = 9 \times 10^9 \text{ N m}^2/\text{C}^2
  • Assumed charge, q=1.6×10−19q = 1.6 \times 10^{-19} C
  • Distance, r=2r = 2 m

  1. Use the formula for the electric field intensity (EE) due to a point charge.

    E=k∣q∣r2E = k \frac{|q|}{r^2}

  2. Substitute the given and assumed values into the formula.

    E=(9×109 N m2/C2)∣1.6×10−19 C∣(2 m)2E = (9 \times 10^9 \text{ N m}^2/\text{C}^2) \frac{|1.6 \times 10^{-19} \text{ C}|}{(2 \text{ m})^2}

  3. Calculate the electric field intensity.

    E=(9×109)1.6×10−194 N/CE = (9 \times 10^9) \frac{1.6 \times 10^{-19}}{4} \text{ N/C} E=(9×109)×(0.4×10−19) N/CE = (9 \times 10^9) \times (0.4 \times 10^{-19}) \text{ N/C} E=3.6×10−10 N/CE = 3.6 \times 10^{-10} \text{ N/C} E=3.6×10−10 N/CE = \boxed{\mathbf{3.6 \times 10^{-10} \text{ N/C}}}
Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

More Physics Questions

QCalculate the electric field at a point 2.0 m away from a 4.0 nC charge, and the forces between…QTwo point charges, q1 = 2.1 imes 10⁻⁵ ext C and q2 = 4q1, are separated by a distance of 10 cm…QCalculate the magnitude and direction of the electric field at the origin due to two charges?Q(continued): The magnitude of the electric field dE created by a point charge dq at a distance d…QCalculate the electrostatic force between two point charges q1 = 2 imes 10⁻⁷ C and q2 = 3 imes 10⁻⁷…
Browse by topic:Electromagnetism
See all Physics questions →
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp