You're on a roll — Here is the solution for question 2. The question asks to calculate the electric field intensity at a point in air situated at a distance of $2$ m from a charge. The value of the charge is partially cut off in the image. I will assume the charge is the elementary charge, $q = 1.6 \times 10^{-19}$ C, as it is a common value in such problems and appears in your notes above this question. If the charge value is different, please provide it. Constants used: • Coulomb's constant, $k = 9 \times 10^9 \text{ N m}^2/\text{C}^2$ • Assumed charge, $q = 1.6 \times 10^{-19}$ C • Distance, $r = 2$ m Step 1: Use the formula for the electric field intensity ($E$) due to a point charge. $$E = k \frac{|q|}{r^2}$$ Step 2: Substitute the given and assumed values into the formula. $$E = (9 \times 10^9 \text{ N m}^2/\text{C}^2) \frac{|1.6 \times 10^{-19} \text{ C}|}{(2 \text{ m})^2}$$ Step 3: Calculate the electric field intensity. $$E = (9 \times 10^9) \frac{1.6 \times 10^{-19}}{4} \text{ N/C}$$ $$E = (9 \times 10^9) \times (0.4 \times 10^{-19}) \text{ N/C}$$ $$E = 3.6 \times 10^{-10} \text{ N/C}$$ $$E = \boxed{\mathbf{3.6 \times 10^{-10} \text{ N/C}}}$$ What's next?