This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
To find the weight of the water raised in the capillary tube, we can use the formula for weight, which is mass times acceleration due to gravity (W = mg). The mass of the water can be found by multiplying its density by its volume (m = V). The volume of the water in the capillary tube is the volume of a cylinder, V = r^2 h. From the previous question (Q11), we have the following values: • Radius of the capillary tube, r = 0.5 mm = 0.5 × 10^-3 m • Density of water, = 1000 kg/m^3 • Acceleration due to gravity, g = 9.8 m/s^2 • Height of water raised, h = (2 )/( g r). From the previous calculation, we found h = (3)/(98) m. Step 1: Calculate the volume of the raised water. The volume of the cylindrical column of water is V = r^2 h. V = × (0.5 × 10^-3 m)^2 × ((3)/(98) m) V = × (0.25 × 10^-6 m^2) × ((3)/(98) m) V = (0.75 )/(98) × 10^-6 m^3 Step 2: Calculate the mass of the raised water. The mass is m = V. m = (1000 kg/m^3) × ((0.75 )/(98) × 10^-6 m^3) m = (0.75 )/(98) × 10^-3 kg Step 3: Calculate the weight of the raised water. The weight is W = mg. W = ((0.75 )/(98) ×