This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Hey MS, good to see you again. Step 1: Identify the given forces and their directions. The first force F_1 is 3 \, N acting Due North. The second force F_2 is 4 \, N acting Due East. Since North and East are perpendicular directions, the angle between the two forces is 90^. Step 2: Calculate the magnitude of the resultant force. The magnitude of the resultant force R of two perpendicular forces can be found using the Pythagorean theorem: |R| = sqrt(F_1^2 + F_2^2) |R| = sqrt((3 \, N))^2 + (4 \, N)^2 |R| = sqrt(9 \, N)^2 + 16 \, N^2 |R| = sqrt(25 \, N)^2 |R| = 5 \, N Step 3: Determine the direction of the resultant force. Let be the angle the resultant force makes with the East direction. = OppositeAdjacent = (F_1)/(F_2) = 3 \, N4 \, N = 0.75 = (0.75) ≈ 36.87^ So, the resultant force is 5 \, N at an angle of approximately 36.87^ North of East. Step 4: Determine the equilibrium force. The equilibrium force is a single force that, when added to the original forces, results in a net force of zero. Therefore, the equilibrium force has the same magnitude as the resultant force but acts in the exact opposite direction. Magnitude of equilibrium force: |F_eq| = |R| = 5 \, N Direction of equilibrium force: Since the resultant force is 36.87^ North of East, the equilibrium force will be 36.87^ South of West. The equilibrium force is 5 N at 36.87^ South of West. Send me the next one 📸