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Two protons, initially one stationary and the other moving at 8.2 imes 105 m/s, undergo an elastic collision. If the first proton is deflected by 60^ 0, by what angle is the second proton deflected?

Physics

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25.a) Elastic Collision of Protons

  1. Identify given values and collision type.

    We have an elastic collision between two protons (equal masses, m1=m2=mm_1 = m_2 = m).
    Initial velocity of proton 1: v1i=8.2×105 m/sv_{1i} = 8.2 \times 10^5 \text{ m/s}.
    Initial velocity of proton 2: v2i=0 m/sv_{2i} = 0 \text{ m/s} (stationary).
    Scattering angle of proton 1: θ1=60∘\theta_1 = 60^\circ.

  2. Determine the angle of the second proton.

    For an elastic collision between two particles of equal mass

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