This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Okay, let's use the provided vapor pressure values for pure benzene and pure methylbenzene. Given: Vapor pressure of pure benzene (P_benzene^) = 3.6 × 10^4 Vapor pressure of pure methylbenzene (P_methylbenzene^) = 1.12 × 10^4 Step 1: Calculate the vapor pressure contribution of benzene (P_benzene) using Raoult's Law: P_benzene = X_benzene P_benzene^ Step 2: Calculate the vapor pressure contribution of methylbenzene (P_methylbenzene) using Raoult's Law: P_methylbenzene = X_methylbenzene P_methylbenzene^ Remember that X_methylbenzene = 1 - X_benzene. Here are the updated calculations: | X_benzene | X_methylbenzene | P_benzene = X_benzene × (3.6 × 10^4) | P_methylbenzene = X_methylbenzene × (1.12 × 10^4) | | :------------------- | :------------------------- | :----------------------------------------------------------------- | :----------------------------------------------------------------------- | | 0 | 1 | 0 × 3.6 × 10^4 = 0 | 1 × 1.12 × 10^4 = 1.12 × 10^4 | | 0.25 | 0.75 | 0.25 × 3.6 × 10^4 = 0.9 × 10^4 | 0.75 × 1.12 × 10^4 = 0.84 × 10^4 | | 0.5 | 0.5 | 0.5 × 3.6 × 10^4 = 1.8 × 10^4 | 0.5 × 1.12 × 10^4 = 0.56 × 10^4 | | 0.75 | 0.25 | 0.75 × 3.6 × 10^4 = 2.7 × 10^4 | 0.25 × 1.12 × 10^4 = 0.28 × 10^4 | | 1 | 0 | 1 × 3.6 × 10^4 = 3.6 × 10^4 | 0 × 1.12 × 10^4 = 0 | The respective vapor pressure contributions for benzene are: 0, 0.9 × 10^4, 1.8 × 10^4, 2.7 × 10^4, 3.6 × 10^4 The respective vapor pressure contributions for methylbenzene are: 1.12 × 10^4, 0.84 × 10^4, 0.56 × 10^4, 0.28 × 10^4, 0