Use 3.6×10⁴ for vapor pressure contribution of benzene And then use 1.12×10⁴ for vapor pressure contribution of methylbenzene

$$P_{\text{methylbenzene}} = X_{\text{methylbenzene}} P_{\text{methylbenzene}}^\circ$$

Remember that $X_{\text{methylbenzene}} = 1 - X_{\text{benzene}}$.

Here are the updated calculations:

$X_{\text{benzene}}$	$X_{\text{methylbenzene}}$	$P_{\text{benzene}} = X_{\text{benzene}} \times (3.6 \times 10^4)$	$P_{\text{methylbenzene}} = X_{\text{methylbenzene}} \times (1.12 \times 10^4)$
0	1	$0 \times 3.6 \times 10^4 = 0$	$1 \times 1.12 \times 10^4 = 1.12 \times 10^4$
0.25	0.75	$0.25 \times 3.6 \times 10^4 = 0.9 \times 10^4$	$0.75 \times 1.12 \times 10^4 = 0.84 \times 10^4$
0.5	0.5	$0.5 \times 3.6 \times 10^4 = 1.8 \times 10^4$	$0.5 \times 1.12 \times 10^4 = 0.56 \times 10^4$
0.75	0.25	$0.75 \times 3.6 \times 10^4 = 2.7 \times 10^4$	$0.25 \times 1.12 \times 10^4 = 0.28 \times 10^4$
1	0	$1 \times 3.6 \times 10^4 = 3.6 \times 10^4$	$0 \times 1.12 \times 10^4 = 0$

The respective vapor pressure contributions for benzene are:
$\boxed{\text{0, } 0.9 \times 10^4\text{, } 1.8 \times 10^4\text{, } 2.7 \times 10^4\text{, } 3.6 \times 10^4}$

The respective vapor pressure contributions for methylbenzene are:
$\boxed{1.12 \times 10^4\text{, } 0.84 \times 10^4\text{, } 0.56 \times 10^4\text{, } 0.28 \times 10^4\text{, } 0}$