Using the ideal gas equation (pv=nRT)show that at a given temperature density of a gas is proportional to gas pressure p

Physics

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Step-by-step solution

6 steps

Let's derive the relationship between density and pressure using the ideal gas equation.

  1. Start with the ideal gas equation.

    The ideal gas equation is given by:

    PV=nRTPV = nRT

    where:
    PP = pressure
    VV = volume
    nn = number of moles
    RR = ideal gas constant
    TT = temperature

  2. Express the number of moles (nn) in terms of mass (mm) and molar mass (MM).

    The number of moles (nn) of a gas is its mass (mm) divided by its molar mass (MM):

    n=mMn = \frac{m}{M}
  3. Substitute the expression for nn into the ideal gas equation.

    PV=(mM)RTPV = \left(\frac{m}{M}\right)RT
  4. Rearrange the equation to isolate the density term (ρ=mV\rho = \frac{m}{V}).

    Divide both sides by VV:

    P=(mV)RTMP = \left(\frac{m}{V}\right)\frac{RT}{M}

    Recognize that mV\frac{m}{V} is the density (ρ\rho):

    P=ρRTMP = \rho \frac{RT}{M}
  5. Rearrange to show density as a function of pressure.

    ρ=PMRT\rho = P \frac{M}{RT}
  6. Identify constant terms at a given temperature.

    For a given gas (meaning MM is constant) and at a given temperature (TT is constant), the terms MRT\frac{M}{RT} are all constant. Let's call this constant kk:

    k=MRTk = \frac{M}{RT}

    Therefore, the equation becomes:

    ρ=Pk\rho = Pk

    This shows that density (ρ\rho) is directly proportional to pressure (PP) when the temperature and molar mass are constant.

    Thus, at a given temperature, the density of a gas is proportional to the gas pressure PP.

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