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Using the principle of homogeneity, determine the dimensions of the constant 'a' in the van der Waals equation.

Physics

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Answer

kg⋅m5⋅s−2\text{kg} \cdot \text{m}^5 \cdot \text{s}^{-2}

Step-by-step solution

4 steps
  1. Understand the Principle of Homogeneity.

    The Principle of Homogeneity states that for an equation to be dimensionally consistent, all terms added or subtracted must have the same dimensions. In the given van der Waals equation:

    (P+aV2)(V−b)=RT(P + \frac{a}{V^2})(V - b) = RT

    For the term (P+aV2)(P + \frac{a}{V^2}), the dimensions of PP must be the same as the dimensions of aV2\frac{a}{V^2}.
    Therefore, we can write:

    The base units of P=The base units of aV2\text{The base units of } P = \text{The base units of } \frac{a}{V^2}
  2. Express the relationship to find the base units of aa.

    From the equality above, we can rearrange to solve for the base units of aa:

    The base units of a=(The base units of P)×(The base units of V)2\text{The base units of } a = (\text{The base units of } P) \times (\text{The base units of } V)^2
  3. Determine the base units for Pressure (PP) and Volume (VV).

    • Pressure (PP) is defined as Force per unit Area. Force (FF) has base units of kg⋅m⋅s−2\text{kg} \cdot \text{m} \cdot \text{s}^{-2} (from F=maF=ma). Area (AA) has base units of m2\text{m}^2. So, the base units of P=kg⋅m⋅s−2m2=kg⋅m−1⋅s−2P = \frac{\text{kg} \cdot \text{m} \cdot \text{s}^{-2}}{\text{m}^2} = \text{kg} \cdot \text{m}^{-1} \cdot \text{s}^{-2}.

    • Volume (VV) has base units of m3\text{m}^3.

  4. Substitute the base units into the expression for aa.

    The base units of a=(kg⋅m−1⋅s−2)×(m3)2\text{The base units of } a = (\text{kg} \cdot \text{m}^{-1} \cdot \text{s}^{-2}) \times (\text{m}^3)^2 The base units of a=kg⋅m−1⋅s−2×m6\text{The base units of } a = \text{kg} \cdot \text{m}^{-1} \cdot \text{s}^{-2} \times \text{m}^6

    Combine the powers of m\text{m}:

    The base units of a=kg⋅m(−1+6)⋅s−2\text{The base units of } a = \text{kg} \cdot \text{m}^{(-1+6)} \cdot \text{s}^{-2} The base units of a=kg⋅m5⋅s−2\text{The base units of } a = \text{kg} \cdot \text{m}^5 \cdot \text{s}^{-2}

    The final answer is kg⋅m5⋅s−2\text{kg} \cdot \text{m}^5 \cdot \text{s}^{-2}.

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