Plot graphs of bond dissociation energy for halogens (F2, Cl2, Br2, I2) and boiling points for hydrogen halides (HF, HCl, HBr, HI).

Chemistry
Plot graphs of bond dissociation energy for halogens (F2, Cl2, Br2, I2) and boiling points for hydrogen halides (HF, HCl, HBr, HI).

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Answer

BDE: low F₂ → peak Cl₂ → ↓ to I₂

BP: high HF → sharp ↓ HCl → gradual ↑ HI

Step 1: Bond dissociation energies of halogens (\ceF2\ce{F2}, \ceCl2\ce{Cl2}, \ceBr2\ce{Br2}, \ceI2\ce{I2})

Values (in \sikJ.mol1\si{kJ.mol^{-1}}):

\ceF2:159 \sikJ.mol1\ceCl2:243 \sikJ.mol1\ceBr2:193 \sikJ.mol1\ceI2:151 \sikJ.mol1\begin{align*} \ce{F2}&: && 159~\si{kJ.mol^{-1}} \\ \ce{Cl2}&: && 243~\si{kJ.mol^{-1}} \\ \ce{Br2}&: && 193~\si{kJ.mol^{-1}} \\ \ce{I2}&: && 151~\si{kJ.mol^{-1}} \end{align*}

Trend: Plot points at these values. Connect with a line: starts low at \ceF2\ce{F2} (weak bond due to lone pair repulsion), peaks high at \ceCl2\ce{Cl2}, then decreases steadily to \ceI2\ce{I2} (weaker overlap of large orbitals).

Step 2: Boiling points of hydrogen halides (\ceHF\ce{HF}, \ceHCl\ce{HCl}, \ceHBr\ce{HBr}, \ceHI\ce{HI})

Values (in \siC^\circ\si{C}):

\ceHF:19.5 \siC\ceHCl:85 \siC\ceHBr:67 \siC\ceHI:35 \siC\begin{align*} \ce{HF}&: && 19.5~^\circ\si{C} \\ \ce{HCl}&: && -85~^\circ\si{C} \\ \ce{HBr}&: && -67~^\circ\si{C} \\ \ce{HI}&: && -35~^\circ\si{C} \end{align*}

Trend: Plot points at these values. Connect with a line: sharp drop from \ceHF\ce{HF} (high due to hydrogen bonding) to \ceHCl\ce{HCl}, then gradual increase to \ceHI\ce{HI} (increasing London dispersion forces with molecular size).

Sketched trends match data points and lines described above.
BDE: low F₂ → peak Cl₂ → ↓ to I₂

BP: high HF → sharp ↓ HCl → gradual ↑ HI

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Quick Answer

Bond dissociation energies of halogens (F2, Cl2, Br2, I2) Values (in kJ.mol^-1): F2&: && 159~kJ.mol^-1 \\ Cl2&: && 243~kJ.mol^-1 \\ Br2&: && 193~kJ.mol^-1 \\ I2&: && 151~kJ.mol^-1 Trend: Plot points at these values.

Plot graphs of bond dissociation energy for halogens (F2, Cl2, Br2, I2) and boiling points for hydrogen halides (HF, HCl, HBr, HI).
Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI Answer
Step 1: Bond dissociation energies of halogens (F2, Cl2, Br2, I2) Values (in kJ.mol^-1): F2&: && 159~kJ.mol^-1 \\ Cl2&: && 243~kJ.mol^-1 \\ Br2&: && 193~kJ.mol^-1 \\ I2&: && 151~kJ.mol^-1 Trend: Plot points at these values. Connect with a line: starts low at F2 (weak bond due to lone pair repulsion), peaks high at Cl2, then decreases steadily to I2 (weaker overlap of large orbitals). Step 2: Boiling points of hydrogen halides (HF, HCl, HBr, HI) Values (in ^): HF&: && 19.5~^ \\ HCl&: && -85~^ \\ HBr&: && -67~^ \\ HI&: && -35~^ Trend: Plot points at these values. Connect with a line: sharp drop from HF (high due to hydrogen bonding) to HCl, then gradual increase to HI (increasing London dispersion forces with molecular size). Sketched trends match data points and lines described above. BDE: low F₂ → peak Cl₂ → ↓ to I₂ BP: high HF → sharp ↓ HCl → gradual ↑ HI