A conductor of length 10 cm carries a current of 2A in a vertical direction. A point P is placed 1 m away from the conductor in the X-direction. Determine the angle between the vertical axis and point P, and the magnetic field at point P using Biot-Savart law.

Step 1: Visualize the arrangement and define parameters.
Let the conductor lie along the y-axis (vertical direction), centered at the origin.
The current $I$ flows in the positive y-direction.
The length of the conductor is $L = 10 \text{ cm} = 0.1 \text{ m}$.
The current is $I = 2 \text{ A}$.
Point P is located $1 \text{ m}$ away from the conductor in the X-direction. So, the perpendicular distance from the conductor to point P is $D = 1 \text{ m}$.
We use the permeability of free space, $\mu_0 = 4\pi \times 10^{-7} T\cdot\