What was the distance covered between point b and c

Physics

ScanSolve AI Answer

Answer

120 m\text{120 m}

Step-by-step solution

2 steps

Here's the calculation for the distance covered between point B and C:

  1. Identify the speeds and time interval for segment BC from the graph.

    At point B, the speed is 20 m/s20\, \text{m/s} at t=10 st = 10\, \text{s}.
    At point C, the speed is 40 m/s40\, \text{m/s} at t=14 st = 14\, \text{s}.
    The time interval is Δt=14 s−10 s=4 s\Delta t = 14\, \text{s} - 10\, \text{s} = 4\, \text{s}.

  2. Calculate the distance covered, which is the area of the trapezium under the graph for segment BC.

    Distance=12×(initial speed+final speed)×time interval\text{Distance} = \frac{1}{2} \times (\text{initial speed} + \text{final speed}) \times \text{time interval} Distance=12×(20 m/s+40 m/s)×4 s\text{Distance} = \frac{1}{2} \times (20\, \text{m/s} + 40\, \text{m/s}) \times 4\, \text{s} Distance=12×(60 m/s)×4 s\text{Distance} = \frac{1}{2} \times (60\, \text{m/s}) \times 4\, \text{s} Distance=30 m/s×4 s\text{Distance} = 30\, \text{m/s} \times 4\, \text{s} Distance=120 m\text{Distance} = 120\, \text{m}

    The distance covered between point B and C is 120 m\text{120 m}.

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