What was the distance covered between point b and c

Here's the calculation for the distance covered between point B and C:

Step 1: Identify the speeds and time interval for segment BC from the graph. At point B, the speed is $20\, \text{m/s}$ at $t = 10\, \text{s}$. At point C, the speed is $40\, \text{m/s}$ at $t = 14\, \text{s}$. The time interval is $\Delta t = 14\, s - 10\, s = 4\, \text{s}$.

Step 2: Calculate the distance covered, which is the area of the trapezium under the graph for segment BC. $Distance = \frac{1}{2} \times (initial speed + final speed) \times time interval$ $Distance = \frac{1}{2} \times (20\, m/s + 40\, m/s) \times 4\, s$ $Distance = \frac{1}{2} \times (60\, m/s) \times 4\, s$ $Distance = 30\, m/s \times 4\, s$ $Distance = 120\, m$ The distance covered between point B and C is $\boxed{120 m}$.

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