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Calculate the wavelength of a wave with a frequency of 1.0 x 1014 Hz and a speed of 3.0 x 108 m/s.

Physics

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Answer

3.0×10−6 m\text{3.0} \times 10^{-6} \, \text{m}

Step-by-step solution

4 steps
  1. Identify the given values.

    The frequency of the waves is f=1.0×1014 Hzf = 1.0 \times 10^{14} \, \text{Hz}.
    The speed of light is c=3.0×108 m/sc = 3.0 \times 10^8 \, \text{m/s}.

  2. Use the wave equation to find the wavelength.

    The relationship between the speed of a wave (cc), its frequency (ff), and its wavelength (λ\lambda) is given by:

    c=fλc = f \lambda

    To find the wavelength (λ\lambda), rearrange the formula:

    λ=cf\lambda = \frac{c}{f}
  3. Substitute the given values into the formula.

    λ=3.0×108 m/s1.0×1014 Hz\lambda = \frac{3.0 \times 10^8 \, \text{m/s}}{1.0 \times 10^{14} \, \text{Hz}}
  4. Calculate the wavelength.

    λ=3.01.0×10(8−14) m\lambda = \frac{3.0}{1.0} \times 10^{(8-14)} \, \text{m} λ=3.0×10−6 m\lambda = 3.0 \times 10^{-6} \, \text{m}

    The wavelength of the signal is 3.0×10−6 m\text{3.0} \times 10^{-6} \, \text{m}.

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