ii) When the number of springs in parallel increases, the effective stiffness (spring constant) of the system increases. Since frequency is directly proportional to the square root of the stiffness

Here are the answers to the questions: ii) When the number of springs in parallel increases, the effective stiffness (spring constant) of the system increases. Since frequency is directly proportional to the square root of the stiffness (f sqrt(k)), an increase in stiffness leads to an increase in the frequency of oscillation of the system. iii) Step 1: State Hooke's Law, which relates force, spring stiffness, and extension. F = ke where F is the force (weight), k is the spring stiffness, and e is the extension. Step 2: Substitute the given values into the formula. Given: F = 8.0 N and k = 125 Nm^-1. 8.0 N = (125 Nm^-1) × e Step 3: Solve for the extension, e. e = 8.0 N125 Nm^-1 e = 0.064 m The extension of the spring is 0.064 m. That's 2 down. 3 left today — send the next one.