We read your photo as:

Explain the inheritance pattern of Congenital Adrenal Hyperplasia (CAH), assuming it's an autosomal recessive condition.

Biology

ScanSolve AI Answer

Step-by-step solution

5 steps
  1. Define alleles.

    Let 'A' represent the dominant allele for normal adrenaline production (no CAH).
    Let 'a' represent the recessive allele for CAH.

  2. Determine parental genotypes.

    Since CAH is a recessive condition, a person must have two recessive alleles (aaaa) to have the condition. Parents who do not have CAH but can have a child with CAH must both be heterozygous carriers. This means each parent has one dominant allele and one recessive allele.
    Parent 1 genotype: AaAa (Normal, carrier)
    Parent 2 genotype: AaAa (Normal, carrier)

  3. Determine parental gametes.

    Each parent will produce two types of gametes:
    Parent 1 gametes: A, a
    Parent 2 gametes: A, a

  4. Construct a Punnett square.

    The Punnett square shows the possible combinations of alleles in their offspring.

    GametesAaAAAAaaAaaa\begin{array}{|c|c|c|} \hline \text{Gametes} & A & a \\ \hline A & AA & Aa \\ \hline a & Aa & aa \\ \hline \end{array}
  5. Explain offspring genotypes and phenotypes.

    From the Punnett square, the possible genotypes for the offspring are:

    • AAAA: 25% chance (Normal, non-carrier)
    • AaAa: 50% chance (Normal, carrier)
    • aaaa: 25% chance (Has CAH)

    Explanation:
    When both parents are heterozygous carriers (AaAa), there is a 25% probability that their child will inherit the recessive allele (aa) from each parent, resulting in the genotype aaaa. A child with the genotype aaaa will express the recessive condition, CAH, even though neither parent has the condition themselves.

    Here is the genetic diagram:
    Parents' phenotypes: Normal (no CAH) ×\times Normal (no CAH)
    Parents' genotypes: Aa×AaAa \times Aa
    Parents' gametes: A,a×A,aA, a \quad \times \quad A, a

    Punnett Square:

    GametesAaAAAAaaAaaa\begin{array}{|c|c|c|} \hline \text{Gametes} & A & a \\ \hline A & AA & Aa \\ \hline a & Aa & aa \\ \hline \end{array}

    Offspring genotypes: 1AA:2Aa:1aa1 AA : 2 Aa : 1 aa
    Offspring phenotypes: 3 Normal (no CAH) : 1 CAH

    This diagram shows that there is a 1 in 4 chance for parents who are both carriers (AaAa) to have a child with CAH (aaaa).

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp