Here is the solution to Activity 1.4: Monohybrid Crossing. Let 'G' represent the dominant allele for yellow seed. Let 'g' represent the recessive allele for green seed. 1.4.1. Indicate the genotype of EACH parent in the first crossing. Parent 1 (heterozygous pea plant with yellow seed): Gg* Parent 2 (purebred pea plant with green seed): gg* 1.4.2. Use the Punnett square method to determine the possible genotype of the offspring in the first crossing. Parental Cross: Gg $\times$ gg $$ \begin{array}{|c|c|c|} \hline \textbf{Gametes} & \textbf{G} & \textbf{g} \\ \hline \textbf{g} & \text{Gg} & \text{gg} \\ \hline \textbf{g} & \text{Gg} & \text{gg} \\ \hline \end{array} $$ The possible genotypes of the offspring are Gg and gg. 1.4.3. Name the type of dominance shown by the crossing in QUESTION 1.4.2. Complete dominance 1.4.4. Explain a reason for the type of dominance in QUESTION 1.4.3. In complete dominance, the heterozygous genotype (Gg) expresses the same phenotype (yellow seed) as the homozygous dominant genotype (GG). The dominant allele (G) completely masks the expression of the recessive allele (g).