01M NaOH gi answer: pH = 12 ni. Way: pOH = 2, pH = 14 − 2 = 12.

Sodium hydroxide ($\text{NaOH}$) is a strong base, so it dissociates completely in water.

$$\text{NaOH} \rightarrow \text{Na}^{+} + \text{OH}^{-}$$

Therefore, the concentration of hydroxide ions $[\text{OH}^{-}]$ is equal to the initial concentration of $\text{NaOH}$.

$$[\text{OH}^{-}] = 0.01 \text{ M}$$

The pOH is defined as the negative logarithm (base 10) of the hydroxide ion concentration.

$$\text{pOH} = -\log_{10}[\text{OH}^{-}]$$ $$\text{pOH} = -\log_{10}(0.01)$$ $$\text{pOH} = -\log_{10}(10^{-2})$$ $$\text{pOH} = -(-2)$$ $$\text{pOH} = 2$$

At 25°C, the sum of pH and pOH is 14.

$$\text{pH} + \text{pOH} = 14$$ $$\text{pH} = 14 - \text{pOH}$$ $$\text{pH} = 14 - 2$$ $$\text{pH} = 12$$