What is the pH value of 0.02M NaOH

Sodium hydroxide (NaOH) is a strong base, meaning it dissociates completely in water.
Therefore, the concentration of hydroxide ions ($\text{OH}^{-}$) is equal to the initial concentration of NaOH.

$$[\text{OH}^{-}] = 0.02 \, \text{M}$$

The pOH is calculated using the formula:

$$\text{pOH} = -\log_{10}[\text{OH}^{-}]$$ $$\text{pOH} = -\log_{10}(0.02)$$ $$\text{pOH} \approx 1.70$$

The relationship between pH and pOH at 25°C is:

$$\text{pH} + \text{pOH} = 14$$ $$\text{pH} = 14 - \text{pOH}$$ $$\text{pH} = 14 - 1.70$$ $$\text{pH} = 12.30$$

The pH value of 0.02 M NaOH is 12.30.