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Calculate the molarity of a 0.5 L solution containing 4 g of NaOH.

May 27, 2026Chemistry

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Answer

\text{0.2 M}

4 steps

Calculate the molar mass of NaOH.
The molar mass of sodium (Na) is $22.99 \, \text{g/mol}$ .
The molar mass of oxygen (O) is $16.00 \, \text{g/mol}$ .
The molar mass of hydrogen (H) is $1.01 \, \text{g/mol}$ .
$\text{Molar mass of NaOH} = (22.99 + 16.00 + 1.01) \, \text{g/mol} = 40.00 \, \text{g/mol}$
Calculate the number of moles of NaOH.
$\text{Moles of NaOH} = \frac{\text{Mass of NaOH}}{\text{Molar mass of NaOH}} = \frac{4 \, \text{g}}{40.00 \, \text{g/mol}} = 0.1 \, \text{mol}$
Convert the volume of the solution from milliliters to liters.
$\text{Volume of solution} = 500 \, \text{mL} = \frac{500}{1000} \, \text{L} = 0.5 \, \text{L}$
Calculate the molarity of the solution.
Molarity is defined as moles of solute per liter of solution.
$\text{Molarity (M)} = \frac{\text{Moles of solute}}{\text{Volume of solution in L}} = \frac{0.1 \, \text{mol}}{0.5 \, \text{L}} = 0.2 \, \text{M}$
The molarity of the solution is $\text{0.2 M}$ .

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