This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Welcome back — missed you this week. 1. Molarity of NaOH solution Step 1: Calculate the molar mass of KHP (KHC_8H_4O_4). Molar mass of KHP = (1 × 39.098) + (5 × 1.008) + (8 × 12.011) + (4 × 15.999) = 204.222 g/mol Step 2: Calculate the moles of KHP. Moles of KHP = Mass of KHPMolar mass of KHP = 0.8234 g204.222 g/mol = 0.0040319 mol Step 3: Determine the moles of NaOH. The reaction between KHP and NaOH is 1:1. KHC_8H_4O_4 (aq) + NaOH (aq) → KNaC_8H_4O_4 (aq) + H_2O (l) Therefore, moles of NaOH = moles of KHP = 0.0040319 mol. Step 4: Convert the volume of NaOH to liters. Volume of NaOH = 38.76 cm^3 = 38.76 mL = 0.03876 L Step 5: Calculate the molarity of the NaOH solution. Molarity of NaOH = Moles of NaOHVolume of NaOH (L) = 0.0040319 mol0.03876 L = 0.10403 M The exact molarity of the NaOH solution is 0.1040 M. 2. Concentration of the diluted FeCl_3 solution Step 1: Identify the given values for dilution. Initial concentration (M_1) = 3.47 × 10^-2 M Initial volume (V_1) = 5.00 cm^3 Final volume (V_2) = 250 cm^3 Step 2: Use the dilution formula M_1V_1 = M_2V_2. (3.47 × 10^-2 M) × (5.00 cm^3) = M_2 × (250 cm^3) Step 3: Solve for M_2. M_2 = (3.47 × 10^-2 M) × (5.00 cm^3)250 cm^3 M_2 = 0.1735 M · cm^3250 cm^3 M_2 = 0.000694 M = 6.94 × 10^-4 M The concentration of the diluted solution is 6.94 × 10^-4 M. 3. Molarity of the FeCl_3 (aq) solution Step 1: Calculate the molar mass of FeCl_3. Molar mass of FeCl_3 = (1 × 55.845) + (3 × 35.453) = 55.845 + 106.359 = 162.204 g/mol Step 2: Calculate the moles of FeCl_3. Moles of FeCl_3 = Mass of FeCl_3Molar mass of FeCl_3 = 0.563 g162.204 g/mol = 0.0034709 mol Step 3: Convert the volume of the solution to liters. Volume of solution = 100.0 mL = 0.1000 L Step 4: Calculate the molarity of the FeCl_3 solution. Molarity of FeCl_3 = Moles of FeCl_3Volume of solution (L) = 0.0034709 mol0.1000 L = 0.034709 M The molarity of the FeCl_3 (aq) solution is 0.0347 M. 4. Concentration of the diluted solution Step 1: Identify the given values for dilution. Initial concentration (M_1) = 0.03477 M (using the provided answer from question 3 for consistency) Initial volume (V_1) = 5.00 cm^3 Final volume (V_2) = 250 cm^3 Step 2: Use the dilution formula M_1V_1 = M_2V_2. (0.03477 M) × (5.00 cm^3) = M_2 × (250 cm^3) Step 3: Solve for M_2. M_2 = (0.03477 M) × (5.00 cm^3)250 cm^3 M_2 = 0.17385 M · cm^3250 cm^3 M_2 = 0.0006954 M The concentration of the diluted solution is 0.0006954 M.