Calculate the pH of the solution after adding 20.0 mL of 0.100 M NaOH to 30.0 mL of 0.100 M HNO₃.

March 30, 2026Chemistry

ScanSolve AI Answer

March 30, 2026

Step 1: Calculate initial moles of HNO₃. $\text{Moles of HNO}_3 = (0.0300 L) \times (0.100 mol/L) = 0.00300 \text{ mol}$

Step 2: Calculate moles of NaOH added. $\text{Moles of NaOH} = (0.0200 L) \times (0.100 mol/L) = 0.00200 \text{ mol}$

Step 3: The reaction is $\text{HNO}_3(aq) + NaOH(aq) \rightarrow NaNO_3(\text

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Calculate initial moles of HNO₃. Moles of HNO_3 = (0.0300 L) × (0.100 mol/L) = 0.00300 mol Step 2: Calculate moles of NaOH added.

Asked on March 30, 2026Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI AnswerAnswered on March 30, 2026

Step 1: Calculate initial moles of HNO₃. Moles of HNO_3 = (0.0300 L) × (0.100 mol/L) = 0.00300 mol Step 2: Calculate moles of NaOH added. Moles of NaOH = (0.0200 L) × (0.100 mol/L) = 0.00200 mol Step 3: The reaction is $HNO_3(aq) + NaOH(aq) → NaNO_3(