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Calculate the pH of the solution after adding 20.0 mL of 0.100 M NaOH to 30.0 mL of 0.100 M HNO₃.

Chemistry

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Step-by-step solution

3 steps
  1. Calculate initial moles of HNO₃.

    Moles of HNO3=(0.0300 L)×(0.100 mol/L)=0.00300 mol\text{Moles of HNO}_3 = (0.0300 \text{ L}) \times (0.100 \text{ mol/L}) = 0.00300 \text{ mol}
  2. Calculate moles of NaOH added.

    Moles of NaOH=(0.0200 L)×(0.100 mol/L)=0.00200 mol\text{Moles of NaOH} = (0.0200 \text{ L}) \times (0.100 \text{ mol/L}) = 0.00200 \text{ mol}
  3. The reaction is $\text{HNO}_3(aq) + NaOH(aq) \rightarrow NaNO_3(\text

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