What volume of 0.1M sodium hydroxide solution :a, contains 0.0025mole of sodium hydroxide?

Mathematics

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Answer

0.025 L\text{0.025 L}

25 mL\text{25 mL}

Step-by-step solution

4 steps
  1. Recall the formula for molarity.

    Molarity (MM) is defined as moles of solute per liter of solution.

    M=moles of solutevolume of solution (L)M = \frac{\text{moles of solute}}{\text{volume of solution (L)}}
  2. Rearrange the formula to solve for volume.

    volume of solution (L)=moles of soluteM\text{volume of solution (L)} = \frac{\text{moles of solute}}{M}
  3. Substitute the given values into the formula.

    Given:
    Moles of sodium hydroxide = 0.0025 mol
    Molarity of sodium hydroxide solution = 0.1 M

    volume of solution (L)=0.0025 mol0.1 M\text{volume of solution (L)} = \frac{0.0025 \text{ mol}}{0.1 \text{ M}} volume of solution (L)=0.025 L\text{volume of solution (L)} = 0.025 \text{ L}
  4. Convert the volume from liters to milliliters (optional, but common for small volumes).

    volume of solution (mL)=0.025 L×1000 mL1 L\text{volume of solution (mL)} = 0.025 \text{ L} \times \frac{1000 \text{ mL}}{1 \text{ L}} volume of solution (mL)=25 mL\text{volume of solution (mL)} = 25 \text{ mL}

    The volume of 0.1 M sodium hydroxide solution that contains 0.0025 mole of sodium hydroxide is 0.025 L\boxed{\text{0.025 L}} or 25 mL\boxed{\text{25 mL}}.

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