This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
The previous response stopped mid-sentence due to an ambiguity in the question. The phrase "a solution of Sodium Hydroxide containing 1 litre" is interpreted as the concentration of the Sodium Hydroxide solution being 1 mol/L. Here's the complete solution for question 1: Step 1: Write the balanced chemical equation for the neutralization. A dibasic acid (H_2A) reacts with Sodium Hydroxide (NaOH). H_2A + 2NaOH → Na_2A + 2H_2O From the equation, 1 mole of dibasic acid reacts with 2 moles of Sodium Hydroxide. Step 2: Calculate the moles of Sodium Hydroxide used. Given: Volume of NaOH = 25 cm^3 = 0.025 L Concentration of NaOH = 1 mol/L (based on the interpretation of "containing 1 litre") Moles of NaOH = Concentration × Volume Moles of NaOH = 1 mol/L × 0.025 L = 0.025 mol Step 3: Calculate the moles of the dibasic acid. Using the mole ratio from the balanced equation (1 mole H_2A : 2 moles NaOH): Moles of H_2A = Moles of NaOH2 = 0.025 mol2 = 0.0125 mol Step 4: Calculate the relative molecular mass of the acid. Given: Mass of dibasic acid = 0.245 g Moles of dibasic acid = 0.0125 mol Relative molecular mass (Molar Mass) = MassMoles Relative molecular mass of H_2A = 0.245 g0.0125 mol = 19.6 g/mol The relative molecular mass of the acid is 19.6. That's 2 down. 3 left today — send the next one.