This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
You're on a roll — Step 1: Calculate the molar mass of sodium hydroxide (NaOH). Molar mass of NaOH = Na + O + H = 23.0 + 16.0 + 1.0 = 40.0g/mol Step 2: Calculate the concentration of NaOH in mol/dm^3. Concentration of NaOH = Mass per litreMolar mass = 8.0g/L40.0g/mol = 0.2mol/dm^3 Step 3: Calculate the moles of NaOH used. Volume of NaOH = 30.0cm^3 = (30.0)/(1000)dm^3 = 0.030dm^3 Moles of NaOH = Concentration × Volume Moles of NaOH = 0.2mol/dm^3 × 0.030dm^3 = 0.006mol Step 4: Write the balanced equation for the neutralization reaction. Let the dibasic acid be H_2A. H_2A(aq) + 2NaOH(aq) Na_2A(aq) + 2H_2O(l) Step 5: Determine the moles of the dibasic acid (H_2A). From the balanced equation, 1mol of H_2A reacts with 2mol of NaOH. Moles of H_2A = (1)/(2) × Moles of NaOH = (1)/(2) × 0.006mol = 0.003mol Step 6: Calculate the relative formula mass of the dibasic acid. Relative formula mass of H_2A = Mass of H_2AMoles of H_2A Relative formula mass of H_2A = 0.294g0.003mol = 98g/mol The relative formula mass of the dibasic acid is 98. What's next?