This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here's how to solve the problem: Step 1: Calculate the pOH of the solution. Given pH = 12. The relationship between pH and pOH is pH + pOH = 14. pOH = 14 - pH = 14 - 12 = 2 Step 2: Calculate the concentration of hydroxide ions, [OH^-], in the final solution. [OH^-] = 10^-pOH = 10^-2 M = 0.01 M Step 3: Calculate the total volume of the solution. The volume of NaOH is 50 mL = 0.050 L. The volume of HCl is 10 mL = 0.010 L. Total Volume = 0.050 L + 0.010 L = 0.060 L Step 4: Calculate the moles of excess OH^- ions in the final solution. Moles of excess OH^- = [OH^-] × Total Volume = 0.01 M × 0.060 L = 0.0006 mol Step 5: Calculate the initial moles of NaOH. Initial moles of NaOH = Concentration of NaOH × Volume of NaOH Initial moles of NaOH = 0.3 M × 0.050 L = 0.015 mol Step 6: Calculate the moles of NaOH that reacted with HCl. The moles of NaOH that reacted are the initial moles minus the excess moles. Moles of NaOH reacted = Initial moles of NaOH - Moles of excess OH^- Moles of NaOH reacted = 0.015 mol - 0.0006 mol = 0.0144 mol Since HCl and NaOH react in a 1:1 molar ratio (HCl + NaOH NaCl + H_2O), the moles of HCl initially present are equal to the moles of NaOH that reacted. Moles of HCl = 0.0144 mol Step 7: Calculate the initial concentration of HCl. Initial concentration of HCl = Moles of HClVolume of HCl Initial concentration of HCl = 0.0144 mol0.010 L = 1.44 M The initial concentration of the acid is 1.44 M. This matches option (b). The final answer is b) 1.44M. Send me the next one 📸