This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here are the solutions to question 3: Part a: Determine the volume of distilled water added. The initial volume of 0.1 M NaOH solution is 5.0 cm^3. The volume of distilled water added is the total volume in the cylinder minus the initial volume of NaOH. For V_1: Total volume = 10.0 cm^3. Volume of distilled water = 10.0 cm^3 - 5.0 cm^3 = 5.0 cm^3 For V_2: Total volume = 10.0 cm^3. Volume of distilled water = 10.0 cm^3 - 5.0 cm^3 = 5.0 cm^3 For V_3: Total volume = 15.0 cm^3. Volume of distilled water = 15.0 cm^3 - 5.0 cm^3 = 10.0 cm^3 For V_4: Total volume = 20.0 cm^3. Volume of distilled water = 20.0 cm^3 - 5.0 cm^3 = 15.0 cm^3 For V_5: Total volume = 25.0 cm^3. Volume of distilled water = 25.0 cm^3 - 5.0 cm^3 = 20.0 cm^3 Part b: Determine the molarity of solutions V_2 and V_3. We use the dilution formula M_1V_1 = M_2V_2, where M_1 = 0.1 M and V_1 = 5.0 cm^3. Step 1: Calculate the molarity for V_2. The total volume for V_2 is 10.0 cm^3. M_2 = (M_1V_1)/(V_2) M_2 = 0.1 M × 5.0 cm^310.0 cm^3 M_2 = (0.5)/(10.0) M M_2 = 0.05 M Step 2: Calculate the molarity for V_3. The total volume for V_3 is 15.0 cm^3. M_2 = (M_1V_1)/(V_3) M_2 = 0.1 M × 5.0 cm^315.0 cm^3 M_2 = (0.5)/(15.0) M M_2 = (1)/(30) M M_2 ≈ 0.0333 M 3 done, 2 left today. You're making progress.