06 g of sodium carbonate, Na2CO3 is contained in 250 cm3 of solution. Calculate the concentration of the solution in a) g dm-3 b) mol dm-3

Here's how to calculate the concentration of the sodium carbonate solution:

a) Concentration in $\text{g dm}^{-3}$

Step 1: Convert the volume of the solution from $\text{cm}^3$ to $\text{dm}^3$. We know that $1 \text{ dm}^3 = 1000 \text{ cm}^3$. $\text{Volume} = 250 \text{ cm}^3 \times \frac{1 \text{ dm}^3}{1000 \text{ cm}^3} = 0.250 \text{ dm}^3$

Step 2: Calculate the concentration in $\text{g dm}^{-3}$. Concentration in $\text{g dm}^{-3}$ is given by the formula: $\text{Concentration} = \frac{\text{Mass of solute}}{\text{Volume of solution}}$ $\text{Concentration} = \frac{1.06 \text{ g}}{0.250 \text{ dm}^3} = \boxed{4.24 \text{ g dm}^{-3}}$

b) Concentration in $\text{mol dm}^{-3}$

Step 1: Calculate the molar mass of sodium carbonate ($\text{Na}_2\text{CO}_3$). Using atomic masses: Na = $23 \text{ g/mol}$, C = $12 \text{ g/mol}$, O = $16 \text{ g/mol}$. $\text{Molar mass of } \text{Na}_2\text{CO}_3 = (2 \times 23) + (1 \times 12) + (3 \times 16)$ $= 46 + 12 + 48 = 106 \text{ g/mol}$

Step 2: Calculate the number of moles of sodium carbonate. $\text{Moles} = \frac{\text{Mass}}{\text{Molar mass}}$ $\text{Moles} = \frac{1.06 \text{ g}}{106 \text{ g/mol}} = 0.01 \text{ mol}$

Step 3: Calculate the concentration in $\text{mol dm}^{-3}$. Concentration in $\text{mol dm}^{-3}$ (molarity) is given by the formula: $\text{Concentration} = \frac{\text{Moles of solute}}{\text{Volume of solution}}$ Using the volume in $\text{dm}^3$ from part (a): $\text{Concentration} = \frac{0.01 \text{ mol}}{0.250 \text{ dm}^3} = \boxed{0.04 \text{ mol dm}^{-3}}$