This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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You're on a roll — here are the calculations for the titration problem: i) Concentration of B in mol/dm^3 Step 1: Calculate the molar mass of sodium carbonate (Na_2CO_3). The atomic masses are Na = 23 g/mol, C = 12 g/mol, O = 16 g/mol. M(Na_2CO_3) = (2 × 23) + 12 + (3 × 16) = 46 + 12 + 48 = 106 \, g/mol Step 2: Calculate the concentration of solution B in mol/dm^3. Solution B contains 6.50 \, g of Na_2CO_3 per dm^3. Concentration of B = Mass concentrationMolar mass = 6.50 \, g/dm^3106 \, g/mol = 0.06132 \, mol/dm^3 The concentration of B is 0.0613 mol/dm^3. ii) Mass concentration of B in g/dm^3 The problem states that solution B contains 6.50 \, g of Na_2CO_3 per dm^3. The mass concentration of B is 6.50 g/dm^3. iii) Concentration of A in g/dm^3 Step 1: Write the balanced chemical equation for the reaction between Na_2CO_3 and H_2SO_4. Na_2CO_3 (aq) + H_2SO_4 (aq) → Na_2SO_4 (aq) + H_2O (l) + CO_2 (g) From the equation, the mole ratio of Na_2CO_3 : H_2SO_4 is 1:1. Step 2: Calculate the concentration of solution A (H_2SO_4) in mol/dm^3 using the titration formula. Given: Concentration of B (C_B) = 0.06132 \, mol/dm^3 Volume of B (V_B) = 25.00 \, cm^3 = 0.02500 \, dm^3 Volume of A (V_A) = 22.40 \, cm^3 = 0.02240 \, dm^3 Mole ratio (n_A/n_B) = 1/1 The titration formula is (C_A V_A)/(n_A) = (C_B V_B)/(n_B). C_A = (C_B V_B n_A)/(V_A n_B) = 0.06132 \, mol/dm^3 × 0.02500 \, dm^3 × 10.02240 \, dm^3 × 1 = 0.0684375 \, mol/dm^3 Step 3: Calculate the molar mass of sulfuric acid (H_2SO_4). The atomic masses are H = 1 g/mol, S = 32 g/mol, O = 16 g/mol. M(H_2SO_4) = (2 × 1) + 32 + (4 × 16) = 2 + 32 + 64 = 98 \, g/mol Step 4: Convert the concentration of A from mol/dm^3 to g/dm^3. Concentration of A (g/dm^3) = Concentration of A (mol/dm^3) × Molar mass of H_2SO_4 Concentration of A = 0.0684375 \, mol/dm^3 × 98 \, g/mol = 6.706875 \, g/dm^3 Rounding to three significant figures, the concentration of A is 6.71 g/dm^3. 4 down, 1 left today. Keep it up!