This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

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\sqrt{\frac{M_2}{M_1}}$$
Solubility is the maximum amount of a solute that can dissolve in a given amount of solvent at a specific temperature to form a saturated solution.
Step 1: Obtain sodium metal and chlorine gas. Step 2: Heat a small piece of sodium metal in a combustion spoon until it starts to burn. Step 3: Carefully lower the burning sodium into a gas jar filled with chlorine gas. Step 4: The sodium will react vigorously with the chlorine gas, producing a bright yellow flame and forming white solid sodium chloride. Step 5: Allow the reaction to complete and cool. Collect the solid sodium chloride formed.
To prepare a solid sample of from , follow these steps:
Step 1: Prepare a soluble lead(II) salt solution from . Since is an insoluble base, it must first be reacted with a dilute acid to form a soluble lead(II) salt. Nitric acid is commonly used as it forms soluble nitrates. Add dilute nitric acid to and warm gently until all the dissolves, forming lead(II) nitrate solution.
Step 2: Precipitate lead(II) sulfate. Add a solution of a soluble sulfate, such as sodium sulfate () or dilute sulfuric acid (), to the lead(II) nitrate solution. Lead(II) sulfate is an insoluble salt and will precipitate out as a white solid. or
Step 3: Isolate and purify the lead(II) sulfate. Filter the mixture to separate the solid precipitate from the solution. Wash the precipitate thoroughly with distilled water to remove any soluble impurities. Dry the solid in an oven or desiccator.
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11. Solubility is the maximum amount of a solute that can dissolve in a given amount of solvent at a specific temperature to form a saturated solution.
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.