A 0.04g of copper metal reacts completely with 25cm cube of 0.5 mol dm cube H2SO4 . Write a chemical equation for the reaction ⁠calculate the molar mass of the copper metal

$$
V_{\text{H}_2\text{SO}_4} = 25 \text{ cm}^3 \times \frac{1 \text{ dm}^3}{1000 \text{ cm}^3} = 0.025 \text{ dm}^3
$$

$$
\text{Moles of H}_2\text{SO}_4 = \text{Concentration} \times \text{Volume}
$$
$$
\text{Moles of H}_2\text{SO}_4 = 0.5 \text{ mol dm}^{-3} \times 0.025 \text{ dm}^3
$$
$$
\text{Moles of H}_2\text{SO}_4 = 0.0125 \text{ mol}
$$

From the balanced equation, the mole ratio of Cu : H₂SO₄ is 1 : 2.
$$
\text{Moles of Cu} = \frac{1}{2} \times \text{Moles of H}_2\text{SO}_4
$$
$$
\text{Moles of Cu} = \frac{1}{2} \times 0.0125 \text{ mol}
$$
$$
\text{Moles of Cu} = 0.00625 \text{ mol}
$$