A label on a bottle of hydrochloric acid has the following information: density 1.134 gm −3 and percentage…

Question

A label on a bottle of hydrochloric acid has the following information: density 1.134 gm −3 and percentage purity 37%. (a) find the mass of the hydrochloric acid in 1cm 3 of the stock.

ScanSolve AI Tutor · Accepted Answer

Haya, twende tukasuluhishe swali hili la kemia.

a) Tafuta masi ya asidi ya hidrokloriki katika $1 \text{ cm}^3$ ya stoki.

Taarifa tulizopewa:

Uzito (density) wa stoki = $1.134 \text{ g cm}^{-3}$ (kwa kudhani $\text{gm}^{-3}$ inamaanisha $\text{g cm}^{-3}$ )
Asilimia ya usafi (percentage purity) = $37\%$

Tafuta masi ya $1 \text{ cm}^3$ ya stoki nzima.
Tunajua fomula ya uzito ni:
$\text{Uzito} = \frac{\text{Masi}}{\text{Kiasi}}$
Hivyo,
$\text{Masi ya stoki} = \text{Uzito} \times \text{Kiasi}$ $\text{Masi ya stoki} = 1.134 \text{ g cm}^{-3} \times 1 \text{ cm}^3$ $\text{Masi ya stoki} = 1.134 \text{ g}$
Tafuta masi ya asidi ya hidrokloriki safi katika $1 \text{ cm}^3$ ya stoki, kwa kutumia asilimia ya usafi.
Asilimia ya usafi inamaanisha kuwa $37\%$ ya masi ya stoki ni asidi ya hidrokloriki safi.
$\text{Masi ya HCl} = \text{Masi ya stoki} \times \frac{\text{Asilimia ya usafi}}{100}$ $\text{Masi ya HCl} = 1.134 \text{ g} \times \frac{37}{100}$ $\text{Masi ya HCl} = 1.134 \text{ g} \times 0.37$ $\text{Masi ya HCl} = 0.41958 \text{ g}$
Ikiwa imerekebishwa kwa sehemu tatu za desimali:
$\text{Masi ya HCl} \approx \boxed{0.420 \text{ g}}$

A label on a bottle of hydrochloric acid has the following information: density 1.134 gm -3 and percentage purity 37%. (a) find the mass of the hydrochloric acid in 1cm 3 of the stock.

Answer

Step-by-step solution

Tafuta masi ya $1 \text{ cm}^3$ ya stoki nzima.

Tafuta masi ya asidi ya hidrokloriki safi katika $1 \text{ cm}^3$ ya stoki, kwa kutumia asilimia ya usafi.

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