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A) State Faraday's first law of electrolysis. b) Calculate the volume of chlorine gas liberated at s.t.p. when a current of 100 A is passed for 2 hours through molten sodium chloride.

Chemistry

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  1. a) Faraday's first law of electrolysis states that the mass of a substance deposited or liberated at an electrode is directly proportional to the quantity of electricity passed through the electrolyte.

  2. b) To calculate the volume of chlorine gas liberated at s.t.p.:

  1. Calculate the total charge (QQ) passed.

    The current (II) is 100 A100 \text{ A}.
    The time (tt) is 2 hours2 \text{ hours}.
    Convert time to seconds:

    t=2 hours×60minuteshour×60secondsminute=7200 st = 2 \text{ hours} \times 60 \frac{\text{minutes}}{\text{hour}} \times 60 \frac{\text{seconds}}{\text{minute}} = 7200 \text{ s}

    Calculate charge:

    Q=I×t=100 A×7200 s=720000 CQ = I \times t = 100 \text{ A} \times 7200 \text{ s} = 720000 \text{ C}
  2. Determine the moles of electrons.

    The Faraday constant (FF) is 96500 C/mol96500 \text{ C/mol}.

    Moles of electrons=QF=720000 C96500 C/mol≈7.46114 mol\text{Moles of electrons} = \frac{Q}{F} = \frac{720000 \text{ C}}{96500 \text{ C/mol}} \approx 7.46114 \text{ mol}
  3. Write the half-reaction for chlorine gas liberation and find moles of Cl2\text{Cl}_2.

    In molten sodium chloride, chlorine gas is liberated at the anode:

    2Cl−(l)→Cl2(g)+2e−2\text{Cl}^-(l) \to \text{Cl}_2(g) + 2\text{e}^-

    From the reaction, 2 moles of electrons produce 1 mole of Cl2\text{Cl}_2.

    Moles of Cl2=Moles of electrons2=7.46114 mol2≈3.73057 mol\text{Moles of } \text{Cl}_2 = \frac{\text{Moles of electrons}}{2} = \frac{7.46114 \text{ mol}}{2} \approx 3.73057 \text{ mol}
  4. Calculate the volume of Cl2\text{Cl}_2 at s.t.p.

    The molar gas volume (MGV\text{MGV}) at s.t.p. is 22.4 dm3/mol22.4 \text{ dm}^3/\text{mol}.

    Volume of Cl2=Moles of Cl2×MGV=3.73057 mol×22.4dm3mol≈83.565 dm3\text{Volume of } \text{Cl}_2 = \text{Moles of } \text{Cl}_2 \times \text{MGV} = 3.73057 \text{ mol} \times 22.4 \frac{\text{dm}^3}{\text{mol}} \approx 83.565 \text{ dm}^3

    The volume of chlorine gas liberated at s.t.p. is 83.57 dm3\boxed{\text{83.57 dm}^3}.

    1. c) Three applications of electrolysis are:
    • Electroplating, such as coating a metal object with a layer of another metal (e.g., silver plating).
    • Extraction of reactive metals from their ores, such as aluminium from bauxite.
    • Purification of metals, such as refining crude copper.
    1. a) Solubility in Chemistry is defined as the maximum mass of a solute that can dissolve in a given mass of solvent (usually 100 g100 \text{ g}) at a specific temperature to form a saturated solution.

    2. b) The table shows the solubility of potassium chlorate (V) at different temperatures: | Mass of KClO3\text{KClO}_3 in grams per 100g100\text{g} of water | 40.0 | 20.0 | 13.3 | 10.0 | 8.0 | |---|---|---|---|---|---| | Temperature (∘C^\circ\text{C}) | 88.0 | 52.0 | 38.0 | 31.0 | 25.0 |

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