This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Aduah, let's balance another equation.
Consider the combustion of methane:
Step 1: Count the atoms of each element on both sides of the unbalanced equation. Reactants: Carbon (C): 1, Hydrogen (H): 4, Oxygen (O): 2 Products: Carbon (C): 1, Hydrogen (H): 2, Oxygen (O): 3 (2 from and 1 from )
Step 2: Balance carbon atoms. In this equation, carbon is already balanced with 1 atom on each side.
Step 3: Balance hydrogen atoms. There are 4 hydrogen atoms on the reactant side () and 2 hydrogen atoms on the product side (). To balance hydrogen, place a coefficient of 2 in front of .
Step 4: Re-count the atoms after balancing hydrogen. Reactants: Carbon (C): 1, Hydrogen (H): 4, Oxygen (O): 2 Products: Carbon (C): 1, Hydrogen (H): , Oxygen (O): (from ) (from )
Step 5: Balance oxygen atoms. There are 2 oxygen atoms on the reactant side () and 4 oxygen atoms on the product side. To balance oxygen, place a coefficient of 2 in front of .
Step 6: Verify that all atoms are balanced. Reactants: Carbon (C): 1, Hydrogen (H): 4, Oxygen (O): Products: Carbon (C): 1, Hydrogen (H): , Oxygen (O): (from ) (from )
The equation is now balanced.
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Aduah, let's balance another equation. Consider the combustion of methane: CH_4 + O_2 → CO_2 + H_2O Step 1: Count the atoms of each element on both sides of the unbalanced equation.
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.