This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Separate the reaction into two half-reactions. Oxidation half-reaction: Fe^2+ → Fe^3+ Reduction half-reaction: MnO_4^- → Mn^2+ Step 2: Balance atoms other than oxygen and hydrogen. For the oxidation half-reaction, Fe atoms are already balanced. Fe^2+ → Fe^3+ For the reduction half-reaction, Mn atoms are already balanced. MnO_4^- → Mn^2+ Step 3: Balance oxygen atoms by adding H_2O. Oxidation: No oxygen atoms. Fe^2+ → Fe^3+ Reduction: Add 4H_2O to the right side to balance the 4 oxygen atoms on the left. MnO_4^- → Mn^2+ + 4H_2O Step 4: Balance hydrogen atoms by adding H^+ (since the reaction is in acidic medium). Oxidation: No hydrogen atoms. Fe^2+ → Fe^3+ Reduction: Add 8H^+ to the left side to balance the 8 hydrogen atoms in 4H_2O on the right. 8H^+ + MnO_4^- → Mn^2+ + 4H_2O Step 5: Balance the charge by adding electrons (e^-). Oxidation: Left side charge: +2 Right side charge: +3 Add 1e^- to the right side to balance the charge. Fe^2+ → Fe^3+ + e^- Reduction: Left side charge: (+8) + (-1) = +7 Right side charge: +2 Add 5e^- to the left side to balance the charge. 5e^- + 8H^+ + MnO_4^- → Mn^2+ + 4H_2O Step 6: Multiply the half-reactions by appropriate integers to equalize the number of electrons. The oxidation half-reaction has 1e^-. The reduction half-reaction has 5e^-. Multiply the oxidation half-reaction by 5: 5(Fe^2+ → Fe^3+ + e^-) 5Fe^2+ → 5Fe^3+ + 5e^- The reduction half-reaction remains unchanged: 5e^- + 8H^+ + MnO_4^- → Mn^2+ + 4H_2O Step 7: Add the two balanced half-reactions and cancel common species. 5Fe^2+ + 5e^- + 8H^+ + MnO_4^- → 5Fe^3+ + 5e^- + Mn^2+ + 4H_2O Cancel 5e^- from both sides: 5Fe^2+ + 8H^+ + MnO_4^- → 5Fe^3+ + Mn^2+ + 4H_2O Step 8: Verify that atoms and charges are balanced. Atoms: Mn: 1 on left, 1 on right O: 4 on left, 4 on right Fe: 5 on left, 5 on right H: 8 on left, 8 on right Charge: Left side: 5(+2) + 8(+1) + (-1) = +10 + 8 - 1 = +17 Right side: 5(+3) + (+2) + 0 = +15 + 2 = +17 Both atoms and charges are balanced. The balanced equation is: MnO_4^- + 5Fe^2+ + 8H^+ → Mn^2+ + 5Fe^3+ + 4H_2O Send me the next one 📸